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Julli [10]
2 years ago
8

FREEEEEEE POINTSSSSSSSS

Mathematics
2 answers:
Gnoma [55]2 years ago
5 0

Answer:

PLS BRAINLIEST

Step-by-step explanation:

Naddik [55]2 years ago
3 0

Answer:

ty

Step-by-step explanation:

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I need someone to help me please
zhuklara [117]
<span>the answer is =<span><span>‌<span>7/24</span></span><span>‌</span></span></span>
4 0
3 years ago
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The figure shows graphs of f, f ', f '', and f '''. Identify each curve.
Rzqust [24]
I think the correct answers are:

f ----> d
<span>f' ----> c
</span><span>f'' ---> b 
</span><span>f''' ---> a

f' signifies the slope of the function f. so f" is the slope of the slope and so on.</span>
8 0
3 years ago
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O. Find the domain and range of each of the three restricted functions.
Orlov [11]

The domain and range of the functions sin x, cos x, and tan x will be (-∞, ∞) and [-1, 1], (-∞, ∞) and [-1, 1], and R - (2n + 1)π/2 and (-∞, ∞) respectively.

<h3>What are domain and range?</h3>

The domain means all the possible values of x and the range means all the possible values of y.

The three restricted functions are given below.

f(x) = sin (x)

f(x) = cos (x)

f(x) = tan (x)

Then the domain of the three restricted functions will be

The domain of sin x will be (-∞, ∞).

The domain of cos x will be (-∞, ∞).

The domain of tan x will be R - (2n + 1)π/2.

Then the range of the three restricted functions will be

The range of sin x will be [-1, 1].

The range of cos x will be [-1, 1].

The range of tan x will be (-∞, ∞).

The graph is given below.

More about the domain and range link is given below.

brainly.com/question/12208715

#SPJ1

4 0
1 year ago
We’re getting married bro
Montano1993 [528]

Answer:

It's not that hard so lets get a divorce bro

Step-by-step explanation:

7 0
2 years ago
Please help me solve for x
kkurt [141]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

The shown pair of angles are Co interior angle pair, therefore the sum of those angles is 180°

\qquad \sf  \dashrightarrow \: 130 \degree + 7x + 1 \degree = 180 \degree

\qquad \sf  \dashrightarrow \: 131 \degree + 7x = 180 \degree

\qquad \sf  \dashrightarrow \:  7x= 180 \degree - 131 \degree

\qquad \sf  \dashrightarrow \:  7x= 49 \degree

\qquad \sf  \dashrightarrow \:  x=49 \degree \div 7

\qquad \sf  \dashrightarrow \:  x=7 \degree

The required value of x is 7°

3 0
2 years ago
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