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3 years ago

What is the theoretical probability of landing on a question mark space on your first roll 1/6 1/4 1/3 1/2

Mathematics

2 answers:

erica [24]3 years ago

7 0

Answer:

1/6

Step-by-step explanation:

if there are 6 sides on a dice and the space is 3 moves away, then you have a 1/6 chance of rolling a 3 and landing on it.

Snezhnost [94]3 years ago

7 0

Answer:

it's actually C. 1/3 hope it helps:)

Step-by-step explanation:

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PLZ HELP 10 PTS!!

solniwko [45]

Answer:

Jill's best friend jumped 8/21 feet further than Jill.

Step-by-step explanation:

we have that

Jill jumped 6 1/3 feet

Jill best friend jumped 6 5/7 feet

To find out how much farther did Jill's best friend jumped, subtract the length that Jill jumped from the length that Jill best friend jumped

$6\frac{5}{7}-6\frac{1}{3}$

but first convert mixed number to improper fraction

$6\frac{5}{7}\ ft=\frac{6*7+5}{7}=\frac{47}{7}\ ft$

$6\frac{1}{3}\ ft=\frac{6*3+1}{3}=\frac{19}{3}\ ft$

substitute the values

$\frac{47}{7}-\frac{19}{3}=\frac{47*3-7*19}{21}=\frac{8}{21}\ ft$

therefore

Jill's best friend jumped 8/21 feet further than Jill.

7 0

3 years ago

Read 2 more answers

The function f(x) = x2 + 6x + 3 is transformed such that g(x) = f(x − 2). Find the vertex of g(x).

garri49 [273]

Answer:

(-1,-6)

Step-by-step explanation:

$f(x)=x^2+6x+3$

$g(x)=f(x-2)$

$g(x)=(x-2)^2+6(x-2)+3$ (Replaced x in f with (x-2))

$g(x)=x^2-4x+4+6x-12+3$ (Used $(x+b)^2=x^2+2bx+b^2$ and distributive property)

$g(x)=x^2-4x+6x+4-12+3$ (Gathered like terms)

$g(x)=x^2+2x-5$ (Simplified)

The vertex of a parabola occurs at $(\frac{-b}{2a},g(\frac{-b}{2a})$ .

Let's find $\frac{-b}{2a}$ first.

$\frac{-2}{2(1)}=-1$

Now we can obtain $g(\frac{-b}{2a})$ which is $g(-1)$ in this case:

$g(x)=x^2+2x-5$

$g(-1)=(-1)^2+2(-1)-5$

$g(-1)=1-2-5$

$g(-1)=-1-5$

$g(-1)=-6$ .

The vertex is (-1,-6).

6 0

3 years ago

Determine the correct scientific notation form of the number. 627,000,000

GREYUIT [131]

Answer:

6.27 x 10 ^ 8

Step-by-step explanation:

8 0

3 years ago

Y=3x^2+11x-4 and y=10x-1. solve the system of equations

Mashcka [7]

3x^2+11x-4=10x-1
3x^2+11x-10x-4+1=0
3x^2+x-3=0
Δ=1^1-4*3*(-3)=1+36=37
x1=(-1+V37)/6

x2=( -1-V37)/6

7 0

3 years ago

A practice law exam has 100 questions, each with 5 possible choices. A student took the exam and received 13 out of 100.If the s

Cloud [144]

Answer:

$z=\frac{13-20}{4}=-1.75$

Assuming:

H0: $\mu \geq 20$

H1: $\mu$

$p_v = P(Z$

Step-by-step explanation:

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest (number of correct answers in the test), on this case we now that:

$X \sim Binom(n=100, p=0.2)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

We need to check the conditions in order to use the normal approximation.

$np=100*0.2=20 \geq 10$

$n(1-p)=20*(1-0.2)=16 \geq 10$

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

$E(X)=np=100*0.2=20$

$\sigma=\sqrt{np(1-p)}=\sqrt{100*0.2(1-0.2)}=4$

So we can approximate the random variable X like this:

$X\sim N(\mu =20, \sigma=4)$

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean". The letter $\phi(b)$ is used to denote the cumulative area for a b quantile on the normal standard distribution, or in other words: $\phi(b)=P(z$