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Zolol [24]
3 years ago
14

To find the average(mean) of a set of numbers, you first find the sum of the numbers and then divide the sum by the number of nu

mbers. What is the average of the numbers ?
Mathematics
1 answer:
photoshop1234 [79]3 years ago
8 0

Answer:

what are the numbers you wsnt to find? if you don't know then you've answeref your own question with this, well, question..!

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Timed test
marysya [2.9K]

Answer:

The correct answer should be 5,130

Step-by-step explanation:

the 3 in 513 is in the ones place, if it were ten times greater than 3 that would be 30, or a 3 in the tens place, the 3 in the number 5,130 is in the tens place, making that the correct choice

4 0
3 years ago
A box of cereal states that there are 96 calories in a 3/4 cup serving what is the unit rate for calories per cup? How many cups
riadik2000 [5.3K]

Answer:1

Step-by-step explanation:

3 0
3 years ago
Grayson baked 24 sugar cookies. His family ate 1/3 of the cookies. How many cookies did they eat? How many cookies are left?
horrorfan [7]

Answer:

His family ate 8 sugar cookies.

16 sugar cookies are left.

Step-by-step explanation:

  • His family ate 1/3 <em>of </em>the 24 sugar cookies: 1/3 x 24= 8
  • How many are left: 24-8=16

4 0
3 years ago
Rewrite in Polar Form....<br> x^(2)+y^(2)-6y-8=0
skad [1K]
\bf x^2+y^2-6y-8=0\qquad &#10;\begin{cases}&#10;x^2+y^2=r^2\\\\&#10;y=rsin(\theta)&#10;\end{cases}\implies r^2-6rsin(\theta)=8&#10;\\\\\\&#10;\textit{now, we do some grouping}\implies [r^2-6rsin(\theta)]=8&#10;\\\\\\\&#10;[r^2-6rsin(\theta)+\boxed{?}^2]=8\impliedby &#10;\begin{array}{llll}&#10;\textit{so we need a value there to make}\\&#10;\textit{a perfect square trinomial}&#10;\end{array}

\bf 6rsin(\theta)\iff 2\cdot r\cdot  \boxed{3\cdot sin(\theta)}\impliedby \textit{so there}&#10;\\\\\\&#10;\textit{now, bear in mind we're just borrowing from zero, 0}&#10;\\\\&#10;\textit{so if we add, \underline{whatever}, we also have to subtract \underline{whatever}}

\bf [r^2-6rsin(\theta)\underline{+[3sin(\theta)]^2}]\quad \underline{-[3sin(\theta)]^2}=8\\\\&#10;\left. \qquad  \right.\uparrow \\&#10;\textit{so-called "completing the square"}&#10;\\\\\\\&#10;[r-3sin(\theta)]^2=8+[3sin(\theta)]^2\implies [r-3sin(\theta)]^2=8+9sin^2(\theta)&#10;\\\\\\&#10;r-3sin(\theta)=\sqrt{8+9sin^2(\theta)}\implies r=\sqrt{8+9sin^2(\theta)}+3sin(\theta)
3 0
3 years ago
I need help with 2. 3. 8 and 13 please help me
Crank

Answer:

all work is shown and pictured

6 0
3 years ago
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