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3 years ago

14

To find the average(mean) of a set of numbers, you first find the sum of the numbers and then divide the sum by the number of nu

mbers. What is the average of the numbers ?

1 answer:

photoshop1234 [79]3 years ago

8 0

Answer:

what are the numbers you wsnt to find? if you don't know then you've answeref your own question with this, well, question..!

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marysya [2.9K]

Answer:

The correct answer should be 5,130

Step-by-step explanation:

the 3 in 513 is in the ones place, if it were ten times greater than 3 that would be 30, or a 3 in the tens place, the 3 in the number 5,130 is in the tens place, making that the correct choice

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3 years ago

A box of cereal states that there are 96 calories in a 3/4 cup serving what is the unit rate for calories per cup? How many cups

riadik2000 [5.3K]

Answer:1

Step-by-step explanation:

3 0

3 years ago

Grayson baked 24 sugar cookies. His family ate 1/3 of the cookies. How many cookies did they eat? How many cookies are left?

horrorfan [7]

Answer:

His family ate 8 sugar cookies.

16 sugar cookies are left.

Step-by-step explanation:

His family ate 1/3 <em>of </em>the 24 sugar cookies: 1/3 x 24= 8

How many are left: 24-8=16

4 0

3 years ago

Rewrite in Polar Form....<br> x^(2)+y^(2)-6y-8=0

skad [1K]

$\bf x^2+y^2-6y-8=0\qquad 
\begin{cases}
x^2+y^2=r^2\\\\
y=rsin(\theta)
\end{cases}\implies r^2-6rsin(\theta)=8
\\\\\\
\textit{now, we do some grouping}\implies [r^2-6rsin(\theta)]=8
\\\\\\\
[r^2-6rsin(\theta)+\boxed{?}^2]=8\impliedby 
\begin{array}{llll}
\textit{so we need a value there to make}\\
\textit{a perfect square trinomial}
\end{array}$

$\bf 6rsin(\theta)\iff 2\cdot r\cdot \boxed{3\cdot sin(\theta)}\impliedby \textit{so there}
\\\\\\
\textit{now, bear in mind we're just borrowing from zero, 0}
\\\\
\textit{so if we add, \underline{whatever}, we also have to subtract \underline{whatever}}$

$\bf [r^2-6rsin(\theta)\underline{+[3sin(\theta)]^2}]\quad \underline{-[3sin(\theta)]^2}=8\\\\
\left. \qquad \right.\uparrow \\
\textit{so-called "completing the square"}
\\\\\\\
[r-3sin(\theta)]^2=8+[3sin(\theta)]^2\implies [r-3sin(\theta)]^2=8+9sin^2(\theta)
\\\\\\
r-3sin(\theta)=\sqrt{8+9sin^2(\theta)}\implies r=\sqrt{8+9sin^2(\theta)}+3sin(\theta)$

3 0

3 years ago

I need help with 2. 3. 8 and 13 please help me

Crank

Answer:

all work is shown and pictured

6 0

3 years ago