The cost of parking is an initial cost plus an hourly cost.
The first hour costs $7.
You need a function for the cost of more than 1 hour,
meaning 2, 3, 4, etc. hours.
Each hour after the first hour costs $5.
1 hour: $7
2 hours: $7 + $5 = 7 + 5 * 1 = 12
3 hours: $7 + $5 + $5 = 7 + 5 * 2 = 17
4 hours: $7 + $5 + $5 + $5 = 7 + 5 * 3 = 22
Notice the pattern above in the middle column.
The number of $5 charges you add is one less than the number of hours.
For 2 hours, you only add one $5 charge.
For 3 hours, you add two $5 charges.
Since the number of hours is x, according to the problem, 1 hour less than the number of hours is x - 1.
The fixed charge is the $7 for the first hour.
Each additional hour is $5, so you multiply 1 less than the number of hours,
x - 1, by 5 and add to 7.
C(x) = 7 + 5(x - 1)
This can be left as it is, or it can be simplified as
C(x) = 7 + 5x - 5
C(x) = 5x + 2
Answer: C(x) = 5x + 2
Check:
For 2 hours: C(2) = 5(2) + 2 = 10 + 2 = 12
For 3 hours: C(3) = 5(3) + 2 = 15 + 2 = 17
For 4 hours: C(3) = 5(4) + 2 = 20 + 2 = 22
Notice that the totals for 2, 3, 4 hours here
are the same as the right column in the table above.
Answer:
A) 1/9, 3, 27
Step-by-step explanation:
i think you mean 3^x (and not 3x).
because otherwise none of the answer options withdraw makes any sense.
3^-2 = 1/(3²) = 1/9
3¹ = 3
3³ = 27
Answer:
The solutions are:
Step-by-step explanation:
We have the following quadratic equation
We can rewrite the equation as follows
Now we use the quadratic formula to solve the equation
For an equation of the form 
the quadratic formula is:
In this case:
Then:
Answer:
Option B, 8 / 6
Step-by-step explanation:
Tangent = Opposite / Adjacent
Tangent of ∠A = Opposite / Adjacent
Tan(A) = 8 / 6 which is the same as Option B
Hope this helps!
A= bh divide by 2 so you'll multiply 10x8 the product would be 80 and so you divide 80 by 2 and get 40 as your result.
