All categories

3 years ago

Slope= 9; intercept= 2

Mathematics

2 answers:

Lostsunrise [7]3 years ago

7 0

Answer:

y = 9x + 2

Step-by-step explanation:

The equation of a line with slope m and y-intercept b is

y = mx + b

If you were asked to write the equation of the line with slope = 9 and y-intercept = 2, then the equation is

y = 9x + 2

saveliy_v [14]3 years ago

7 0

Answer:

y = 9x -2

Step-by-step explanation:

You might be interested in

5th grade math homework I really need help on this

adell [148]

So basically you need to multiply 3000x4000 in two ways? If so you can use basic multiplication and an area model

8 0

2 years ago

Read 2 more answers

4. Find the value of the expression below for r=4 and t=2.

Katen [24]

Answer:

(a) 9

Step-by-step explanation:

$\sf t^3 - r + 20 \div r$

substitute r = 4, t = 2

$\sf (2)^3 - 4 + 20 \div 4$

simplify

$\sf (2)^3 - 4 + 5$

cubic of 2 is 8

$\sf 8 - 4 + 5$

simplify

$\sf 9$

5 0

2 years ago

Read 2 more answers

In triangle DEF. DF = 16 and m<F = 45Find the length of a leg. Leave your answer in simplest radical form.

kotegsom [21]

I'm ASSUMING this is a 45-45-90 right triangle and that DF is the hypotenuse.
With that said. Angle F = 45 means that angle = 45 and angle E = 90 degrees.
There is only one rule for 45-45-90 right triangles:
hypotenuse = √(2) * leg
Given the hyp = 16
16 = √(2) * leg
divide both sides by √(2)
16/√(2) = leg
Rationalize the denominator
16√(2)/(√(2)*√(2) =
(16√(2)) / 2 =
8√2

6 0

3 years ago

What is the area of a triangle for one of the legs being 3in and the hypotenuse being 9in

elena55 [62]

The area of a triangle for one of the legs being 3 inches and the hypotenuse being 9 inches is 12.727 square inches

Solution:

Given that to find area of a triangle for one of the legs being 3 inches and the hypotenuse being 9 inches

From given information,

Let "c" = hypotenuse = 9 inches

Let "a" = length of one of the leg of triangle = 3 inches

To find: area of triangle

The area of triangle when hypotenuse and length of one side of triangle is given:

$A = \frac{1}{2} a \sqrt{c^2 - a^2}$

Where, "c" is the length of hypotenuse

"a" is the length of one side of triangle

Substituting the given values we get,

$A = \frac{1}{2} \times 3 \times \sqrt{9^2 - 3^2}$

$A =\frac{1}{2} \times 3 \times \sqrt{81-9}\\\\A =\frac{1}{2} \times 3 \times \sqrt{72}\\\\A =\frac{1}{2} \times 3 \times 8.48528\\\\A = \frac{1}{2} \times 25.45584\\\\A = 12.727$

Thus area of triangle is 12.727 square inches

5 0

3 years ago

Change the following numbers to decimals and round to the nearest hundredth 5/9

love history [14]

Answer:

Answer: 5/9 as a decimal is 0.556.

6 0

2 years ago

Read 2 more answers