You should use a T distribution to find the critical T value based on the level of confidence. The confidence level is often given to you directly. If not, then look for the significance level alpha and compute C = 1-alpha to get the confidence level. For instance, alpha = 0.05 means C = 1-0.05 = 0.95 = 95% confidence
Use either a table or a calculator to find the critical T value. When you find the critical value, assign it to the variable t.
Next, you'll compute the differences of each pair of values. Form a new column to keep everything organized. Sum everything in this new column to get the sum of the differences, which then you'll divide that by the sample size n to get the mean of the differences. Call this dbar (combination of d and xbar)
After that, you'll need the standard deviation of the differences. I recommend using a calculator to quickly find this. A spreadsheet program is also handy as well. Let sd be the standard deviation of the differences
The confidence interval is in the form (L, U)
L = lower bound
L = dbar - t*sd/sqrt(n)
U = upper bound
U = dbar + t*sd/sqrt(n)
Answer:
B
Step-by-step explanation:
5) 2 1 -55
| 10 55
|---------------
2 11 | 0
quotient=2x+11
Answer:
This is an odd question...
The couple should find out the following:
1.) is the agency legitimate?
2.) Will they be doing a hard inquiry on our credit history? if so, this could affect our current credit score
3.) Will they charge me to review my current credit reports?
Answer:
B. 246 in^2
Step-by-step explanation:
A = pi r^2 theta /360 if theta is in degrees
A = * pi *(16)^2 * (110/360)
A = *pi* 256 * 11/36
A = 2816/36 *pi
A = 245.74236 in ^2