What’s the correct answer for this question

Mathematics

1 answer:

HACTEHA [7]3 years ago

6 0

All of them are true except AD = GH.

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From least to greatest would this be right or do I have to change it? 177,156,99,87

harina [27]

Answer:

From least to greatest it would be 87, 99, 156, 177

Step-by-step explanation:

The statement "from least to greatest" means starting from the lowest value and transitioning to the greatest value/

Think of it as least -> greatest.

3 0

3 years ago

Find the values of x and y for which the lines are parallel.

prisoha [69]

This problem is accompanied by a figure.

You can infere these relationships from the figure

(x-5)° = 74° => x = 74 + 5 = 79°

(x-5)° + 58° + (y-1)° = 180 ° => 74 + 58 + y-1 = 180 =>

y = 180 + 1 - 58 - 74 = 47°

Answer: x = 79°, y = 47°. This is the option d)

5 0

3 years ago

If f(x) = 9x10 tan−1x, find f '(x).

djverab [1.8K]

Answer:

$\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = 9x^{10} \tan^{-1}(x)$

Step 2: Differentiate

[Function] Derivative Rule [Product Rule]: $\displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Basic Power Rule: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Arctrig Derivative: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$