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bazaltina [42]
3 years ago
5

g(x) = x3 + 6x2 + 12x + 8 Determine the function’s value when x = −1. g(−1) = −3 g(−1) = 0 g(−1) = 1 g(−1) = 27

Mathematics
2 answers:
Archy [21]3 years ago
6 0

Answer:

option c, g (-1) = 1

Step-by-step explanation:

The given function is g(x) = x³ + 6x² + 12x + 8

and we have to find the value of the function when x (-1) for this we will plug in the value of x = -1 in the function.

g (-1) = (-1)³ + 6 (-1)² + (12) (-1) + 8

        = (-1) + 6 - 12 + 8

       = 14 - 13

        = 1

Therefore, option c, g (-1) = 1 will be the answer.

yawa3891 [41]3 years ago
5 0
The correct answer is that g(-1) = 1.

To do this problem, we have to plug in -1 for x and evaluate the expression.

g(-1) = x^3 + 6x^2 + 12x + 8

(-1)^3 + 6(-1)^2 + 12(-1) + 8

-1 + 6 -12 + 8

1
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