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liraira [26]
3 years ago
8

I need this pleaseeeee!!!!

Mathematics
1 answer:
fiasKO [112]3 years ago
3 0

Answer:

<em><u>the</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>000</u></em><em><u>4</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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Which describes an acute angle?
yawa3891 [41]
A is the corect answer :))
6 0
3 years ago
If lulu equals 6, julie equals 15, joe equals 15 and jill equals 12, what number is each letter worth
Ede4ka [16]
In Lulu, each letter is worth 1.5.

In Julie, each letter is worth 3.

In Joe, each letter is worth 5.

In Jill, each letter equals 3.


Hope this helps! :)


6 0
4 years ago
Help me pleas...<br><img src="https://tex.z-dn.net/?f=%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%2
elena-14-01-66 [18.8K]
One common example for you

7 0
3 years ago
Kendra is considering two different long-distance phone plans. Phone plan A charges a $100 sign-up fee and 3 cents per minute. P
Fed [463]

Answer:

Part 1) The number of minutes in a month must be greater than 50 in order for the plan A to be preferable

Part 2) The number of minutes in a month must be equal to 50 minutes

Step-by-step explanation:

<u><em>The question is</em></u>

Part 1) How many minutes would Kendra have to use in a month in order for the plan A to be preferable? Round your answer to the nearest minute

Part 2) Enter the number of minutes where Kendra will pay the same amount for each long distance phone plan

Part 1)

Let

x ---> the number of minutes

we have

<em>Cost Plan A</em>

3x+100

<em>Cost Plan B</em>

5x

we know that

In order for plan A to be cheaper than plan B, the following inequality must hold true.

cost of plan A < cost of plan B

substitute

3x+100 < 5x

solve for x

subtract 3x both sides

100< 5x-3x\\100

divide by 2 both sides

50 < x

Rewrite

x> 50\ min

therefore

The number of minutes in a month must be greater than 50 in order for the plan A to be preferable

Part 2)

Let

x ---> the number of minutes

we have

<em>Cost Plan A</em>

3x+100

<em>Cost Plan B</em>

5x

we know that

In order for plan A cost the same than plan B, the following equation must hold true.

cost of plan A = cost of plan B

substitute

3x+100= 5x

solve for x

5x-3x=100\\2x=100\\x=50\ min

therefore

The number of minutes in a month must be equal to 50 minutes

5 0
3 years ago
Blake and two friends equally shared the cups of water shown in the picture.
3241004551 [841]
The answer would be c- 2/6

there are six cups total and three (blake plus two others) friends

there are two ways you can solve this…

1. by making groups
if you look at the picture, you can split it into three groups because that is the number of people, then count how many cups there are in one group which will be your numerator for the denominator six which is the total

2. simple division
divide the total number of cups buy the number of people which is 3
you get two and follow the same process above

6 0
3 years ago
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