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Westkost [7]
3 years ago
10

What is the measure of the largest angle of a triangle whose measures are in the ratio 2:3:4

Mathematics
1 answer:
malfutka [58]3 years ago
6 0
2x+3x+4x=180
9x=180
x=20
You might be interested in
Consider a binomial experiment with 15 trials and probability 0.35 of success on a single trial.
DedPeter [7]

Answer:

a

   P(X =  10 ) =  0.0096

b

   P(X = 10 ) =  0.0085

c

 Option A is correct

Step-by-step explanation:

From the question we are told that

     The sample size is   n =  15

     The  probability of success is  p =  0.35

     The number of success we are considering is  r = 10  

 

Now the probability of failure is mathematically evaluated as

        q =  1- p

substituting value

       q =  1- 0.35

       q = 0.65

Now using  the binomial distribution  to find the probability of exactly 10 successes we have that

    P(X =  r ) =  [\left n } \atop {r}} \right. ] * p^r *  q^{n- r}

substituting values

    P(X =  10 ) =  [\left 15 } \atop {10}} \right. ] * p^{10}*  q^{15- 10}

Where  [\left 15 } \atop {10}} \right. ] mean 15 combination 10  which is evaluated with a calculator to obtain  

       [\left 15 } \atop {10}} \right. ]  = 3003

So

      P(X =  10 ) =  3003 * 0.35 ^{10}*  0.65^{15- 10}

       P(X =  10 ) =  0.0096

Now using  the normal distribution to approximate the probability of exactly 10 successes, we have that

  P(X = r ) =  P( r  <  X <   r )

Applying continuity correction

          P(X = r ) =  P( r -0.5 <  X <   r +0.5)

substituting values

        P(X = 10) =  P( 10-0.5 <  X <   10+0.5)

       P(X = 10 ) =  P( 9.5 <  X <   10.5)

Standardizing  

         P(X = r ) =  P( \frac{9.5 -  \mu }{\sigma }  <  \frac{X - \mu }{\sigma }  <  \frac{10.5 - \mu}{\sigma }  )

The  where  \mu is the mean which is mathematically represented as

        \mu  =  n *  p

substituting values

        \mu  =  15 *  0.35

         \mu  =  5.25

The standard deviation is evaluated as      

     \sigma  =  \sqrt{n  *  p  * q }

substituting values

    \sigma  =  \sqrt{15   *  0.35  * 0.65 }

    \sigma  = 1.8473

Thus  

     P(X = 10 ) =  P( \frac{9.5 -  5.25 }{1.8473 }  <  \frac{X - 5.25 }{1.8473 }  <  \frac{10.5 - 5.25}{1.8473 }  )

     P(X = 10 ) =  P( 2.30 < Z <  2.842  )

     P(X = 10 ) = P(Z <  2.842 ) -  P(Z <  2.30   )

From the normal distribution table we obtain the P(Z < 2.841) as

      P(Z < 2.841) = 0.99775

And  the  P(Z < 2.30)

     P(Z < 2.30) =  0.98928

There value can also be obtained from a probability of z calculator at (Calculator dot net website)

So  

    P(X = 10) =   0.99775 - 0.98928

     P(X = 10 ) =  0.0085

Looking at the calculated values for question a and b  we see that the values are fairly different.

8 0
3 years ago
A 50-ft chain with mass density 5 lb/ft is initially coiled on the ground. How much work is performed in lifting the chain so th
tatyana61 [14]
Density is mass/ volume so the answer is 10
6 0
2 years ago
Pl help it’s for a grade I will give you Brainly if right
mixas84 [53]

15ℎ2+26ℎ−21

yes yes yes yes

8 0
2 years ago
Greg feeds his dog 2/3 pounds of dog food for each meal. Greg has just bought 18 pounds of dog food. For how many meals will the
yan [13]
We can divide 18 pounds by 2/3 pounds to find how many servings of meals the dogs will have.
We will use the keep change flip rule to solve this.
18 / 2/3 is then the same as 18 x 3/2
We then multiply across to get
54/2
This would be 27 meals that the food will last
3 0
3 years ago
The graph of y &gt; 1 2 x - 2 is shown. Which set contains only points that satisfy the inequality? A) {(6, 1), (-1, -3), (4, 4)
Kaylis [27]

Answer:

Option B) {(1, -1), (-3, -3), (2, 4)}

Step-by-step explanation:

<u><em>The correct inequality is </em></u>

y>\frac{1}{2}x-2

The solution of the inequality is the shaded area above the dashed line y=\frac{1}{2}x-2

see the attached figure to better understand the problem

we know that

If a ordered pair satisfy the inequality, then the ordered pair must lie in the shaded area of the solution

<u><em>Verify each case</em></u>

case A) {(6, 1), (-1, -3), (4, 4)}

ordered pair (6,1)

For x=6, y=1

substitute in the inequality

1>\frac{1}{2}(6)-2

1>1 ---> is not true

therefore

The point not satisfy the inequality

case B)  {(1, -1), (-3, -3), (2, 4)}

ordered pair (1,-1)

For x=1, y=-1

substitute in the inequality

-1>\frac{1}{2}(1)-2

-1>-1.5 ---> is true

so

The point satisfy the inequality

ordered pair (-3,3)

For x=-3, y=3

substitute in the inequality

3>\frac{1}{2}(-3)-2

3>-3.5 ---> is true

so

The point satisfy the inequality

ordered pair (2,4)

For x=2, y=4

substitute in the inequality

4>\frac{1}{2}(2)-2

4>-1 ---> is true

so

The point satisfy the inequality

therefore

The set contains only points that satisfy the inequality

case C) {(1, -1), (-3, -3), (4, -2)}

ordered pair (4,-2)

For x=4, y=-2

substitute in the inequality

-2>\frac{1}{2}(4)-2

-2>0 ---> is not true

therefore

The point not satisfy the inequality

case D) {(-1, -3), (-3, -3), (2, 4)}

ordered pair (-1,-3)

For x=-1, y=-3

substitute in the inequality

-3>\frac{1}{2}(-1)-2

-3>-2.5 ---> is not true

therefore

The point not satisfy the inequality

4 0
3 years ago
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