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kiruha [24]
3 years ago
7

Leah is buying curtains for her bedroom window. She wants the curtains to hang from the top of the window to the floor. The wind

ow is four feet high. The bottom of the window is 2 feet above the floor. How many inches long should Leah's curtains be? (1 foot = 12 inches)
Mathematics
1 answer:
Fiesta28 [93]3 years ago
3 0
4’+2’=6’

6 feet to inches: 6 x 12 = 72”
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Please help. I don't understand how to solve this problem.
spayn [35]

Answer:

BF=16

Step-by-step explanation:

To find BF, (I will be calling it x) you need to use the equation

CF/FB=CE/EA Substitute

FB=x

24/x=18/12 cross multiply

18x=288 divide both sides by 18

x=16

FB=16

Hope this helps, if it does, please consider giving me brainliest, it will help me a lot.

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3 0
4 years ago
A light bulb is designed by revolving the graph of:
nadya68 [22]

Answer:

\displaystyle 0.251327 \ in. \ of \ glass

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Terms/Coefficients
  • Expand by FOIL (First Outside Inside Last)
  • Factoring

<u>Calculus</u>

Differentiation

Derivative Notation

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Integration

  • Integration Property: \displaystyle \int\limits^a_b {cf(x)} \, dx = c \int\limits^a_b {f(x)} \, dx
  • Fundamental Theorem of Calculus: \displaystyle \int\limits^a_b {f(x)} \, dx = F(b) - F(a)
  • Area between Two Curves
  • Volumes of Revolution
  • Arc Length Formula: \displaystyle AL = \int\limits^a_b {\sqrt{1+ [f'(x)]^2}} \, dx
  • Surface Area Formula: \displaystyle SA = 2\pi \int\limits^a_b {f(x) \sqrt{1+ [f'(x)]^2}} \, dx

Step-by-step explanation:

<u>Step 1: Define</u>

\displaystyle y = \frac{1}{3}x^{\frac{1}{2}} - x^{\frac{3}{2}}\\Interval: [0, \frac{1}{3}]

<u>Step 2: Differentiate</u>

  1. Basic Power Rule:                    \displaystyle y' = \frac{1}{2} \cdot \frac{1}{3}x^{\frac{1}{2} - 1} - \frac{3}{2} \cdot x^{\frac{3}{2} - 1}
  2. [Derivative] Simplify:                \displaystyle y' = \frac{1}{6}x^{\frac{-1}{2}} - \frac{3}{2}x^{\frac{1}{2}}
  3. [Derivative] Simplify:                \displaystyle y' = \frac{1}{6\sqrt{x}} - \frac{3\sqrt{x}}{2}}

<u>Step 3: Integrate Pt. 1</u>

  1. Substitute [Surface Area]:                                                                             \displaystyle SA = 2\pi \int\limits^{\frac{1}{3}}_0 {(\frac{1}{3}x^{\frac{1}{2}} - x^{\frac{3}{2}}) \sqrt{1+ [\frac{1}{6\sqrt{x}} - \frac{3\sqrt{x}}{2}}]^2}} \, dx
  2. [Integral - √Radical] Expand/Add:                                                               \displaystyle SA = 2\pi \int\limits^{\frac{1}{3}}_0 {(\frac{1}{3}x^{\frac{1}{2}} - x^{\frac{3}{2}}) \sqrt{\frac{81x^2+18x+1}{36x}} \, dx
  3. [Integral - √Radical] Factor:                                                                         \displaystyle SA = 2\pi \int\limits^{\frac{1}{3}}_0 {(\frac{1}{3}x^{\frac{1}{2}} - x^{\frac{3}{2}}) \sqrt{\frac{(9x + 1)^2}{36x}} \, dx
  4. [Integral - Simplify]:                                                                                       \displaystyle SA = 2\pi \int\limits^{\frac{1}{3}}_0 {-\frac{|9x + 1|(3x - 1)}{18}} \, dx
  5. [Integral] Integration Property:                                                                     \displaystyle SA = \frac{- \pi}{9} \int\limits^{\frac{1}{3}}_0 {|9x + 1|(3x - 1)} \, dx

<u>Step 4: Integrate Pt. 2</u>

  1. [Integral] Define:                                                                                             \displaystyle \int {|9x + 1|(3x - 1)} \, dx
  2. [Integral] Assumption of Positive/Correction Factors:                                 \displaystyle \frac{9x + 1}{|9x + 1|} \int {(9x + 1)(3x - 1)} \, dx
  3. [Integral] Expand - FOIL:                                                                                 \displaystyle \frac{9x + 1}{|9x + 1|} \int {27x^2 - 6x - 1} \, dx
  4. [Integral] Integrate - Basic Power Rule:                                                         \displaystyle \frac{9x + 1}{|9x + 1|} (9x^3 - 3x^2 - x)
  5. [Expression] Multiply:                                                                                      \displaystyle \frac{(9x + 1)(9x^3 - 3x^2 - x)}{|9x + 1|}

<u>Step 5: Integrate Pt. 3</u>

  1. [Integral] Substitute/Integral - FTC:                                                              \displaystyle SA = \frac{- \pi}{9} (\frac{(9x + 1)(9x^3 - 3x^2 - x)}{|9x + 1|})|\limits_{0}^{\frac{1}{3}}
  2. [Integrate] Evaluate FTC:                                                                                \displaystyle SA = \frac{- \pi}{9} (\frac{-1}{3})
  3. [Expression] Multiply:                                                                                     \displaystyle SA = \frac{\pi}{27} \ ft^2

<em>It is in ft² because it is given that our axis are in ft.</em>

<u>Step 6: Find Amount of Glass</u>

<em>Convert ft² to in² and multiply by 0.015 in (given) to find amount of glass.</em>

  1. Convert ft² to in²:                    \displaystyle \frac{\pi}{27} \ ft^2 \ \div 144 \ in^2/ft^2 = \frac{16 \pi}{3} \ in^2
  2. Multiply:                                   \displaystyle \frac{16 \pi}{3} \ in^2 \cdot 0.015 \ in = 0.251327 \ in. \ of \ glass

And we have our final answer! Hope this helped on your Calc BC journey!

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Step-by-step explanation:

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Step-by-step explanation:

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Nikolay [14]

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Step-by-step explanation:

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