Answer:
1.175 M
Explanation:
Mass = 32.9 g
Volume = 700.0 mL = 0.7 L
Molarity = ?
The relationship between the quantities is given by;
Molarity = Number of moles / Volume
Number pf moles = Mass /Molar mass
Number of moles = 32.9 / 40 = 0.8225 mol
Molarity = 0.8225 / 0.7 = 1.175 M
Answer:
4.44 dm³ of SO₂
Solution:
The balance chemical equation is as follow,
CS₂ + 3 O₂ → CO₂ + 2 SO₂
According to equation,
22.4 dm³ (1 mole) CS₂ produces = 44.8 dm³ (2 mole) of SO₂
So,
2.22 dm³ CS₂ will produce = X dm³ of SO₂
Solving for X,
X = (2.22 dm³ × 44.8 dm³) ÷ 22.4 dm³
X = 4.44 dm³ of SO₂
<u>Answer:</u>
<em>We know water can exist in all three states be it solid or liquid or gas the only difference between the three states is the temperature at which they exist. </em>
<u>Explanation:</u>
When the temperature moves towards colder region the state of water changes to solid while when the temperature moves to water region the state of water changes to gas.
This little experiment can be done with the help of ice at room temperature. The more ice is applied to water it will turn to ice but removal of eyes in room temperature. And will make it turn to water and complete removal of eyes with application of heat would make it into vapour.
The Diprotodon apparently become extinct <u>20,000 years</u> ago.
<h3>Briefly explained</h3>
This question is in reference to the use of carbon 14 dating. We know the specific activity of a Australian marsupial. Based on the carbon 14 present. It's .61 PICO curie program. Modern carbon has a specific activity of 6.89 PICO curie program. So all we need to do then is use the first order integrated rate law to solve for the time that has elapsed with Both of these activities as part of the equation.
But before we can do that we need the decay constant for carbon 14, which we can get by dividing the half life Of carbon 14 into natural log of two. And we get 1.21 times 10 to give 14, 1 over years. So using the first order integrated rate law, the natural log of the activity at time, T divided by the activity Um at time zero represented by present day Will be equal to negative K. multiplied by T.
Little Algebraic rearrangement gives us an age of 20,000 years.
Learn more about decay
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