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3 years ago

6x/6 = −42/6 please answer

Mathematics

1 answer:

VikaD [51]3 years ago

5 0

Answer:

x = -7?

Step-by-step explanation:

how?

the last screenshot couldn't fit so: 6x/6 = -42/6

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3 years ago

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An airplane flies with a constant

lora16 [44]

Answer:

1 hour and 30 minutes.

Here's how I did it:

960/3 = 220

220 = 30 minutes

220 = 30 minutes x 3 = 960

30x3=90

90 has to be converted into minutes and hours

so 90 = 1:30

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3 years ago

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3 years ago

What is the perimeter of the given triangle?

vovikov84 [41]

Answer:

17.2 units

Step-by-step explanation:

You would use the Pythagorean Theorem to solve. The height (a) is 4 units. The base (b) is 6 units.

4^2 + 6^2 = sqrt(52)

This would mean that the hypotenuse is 7.211102550927979 units or 7.2 units (the square root of 4^2 + 6^2).

Now you would need to just add all three sides.
6 + 4 + 7.2 = 17.2 units

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2 years ago

The ages (in years) and weights (in pounds) of all wide receivers for a football team are listed. Find the coefficient of variat

IceJOKER [234]

Answer:

The coefficient of variation for the weight and age are 5.9% and 10.6%.

Step-by-step explanation:

The coefficient of variation (CV) is well defined as the ratio of the standard deviation to the mean. It exhibits the degree of variation in association to the mean of the population.

The formula to compute the coefficient of variation is:

$CV=\frac{\sigma}{\mu}\times 100\%$

Here σ = standard deviation and µ = mean.

Compute the mean and standard deviations of the two data set in Excel using the following functions.

Mean=AVERAGE()

Standard deviation=STDEV.S()

Consider the Excel sheet attached.

The mean and standard deviation of weight are:

Mean = 202, Standard deviation = 11.87

And the mean and standard deviation of weight are:

Mean = 25.88, Standard deviation = 2.75

Compute the coefficient of variation for the weight as follows:

$CV_{weight}=\frac{\sigma}{\mu}\times 100\%$

$=\frac{11.87}{202}\times 100\%\\\\=5.87624\\\\=5.9\%$

Compute the coefficient of variation for the age as follows:

$CV_{age}=\frac{\sigma}{\mu}\times 100\%$

$=\frac{2.75}{25.88}\times 100\%\\\\=10.62597\\\\=10.6\%$

Thus, the coefficient of variation for the weight and age are 5.9% and 10.6%.

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3 years ago