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3 years ago

Help me please. I need the domain and range written as an inequality.

Mathematics

2 answers:

Inga [223]3 years ago

6 0

Answer:

Domain is x-values and range is values

In your picture we see x-coordinates extending towrds the postive section from point (-2,-2)

The inequality is x values greater than or equal -2

x>=-2 for domian

The highest point of y-values is zero or 0 so we can write the inequality as

y is less or equal 0 or y<=0

Step-by-step explanation:

Rainbow [258]3 years ago

5 0

Answer:

y > 2

Step-by-step explanation:

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please help with this it would mean a lot (you don't have to give the answer just help me understand it.) thanks

lord [1]

2.065 IS THE ANSWER!!

4 0

3 years ago

How might this number be shown on a calculator? 5.31x1037 (37 is above 10) [?]e[ ]

Arisa [49]

Answer:

$5.31E37$

Step-by-step explanation:

Given

$5.31 * 10^{37}$

Required

How it'd be displayed on a calculator

Standard calculators, today are built to always convert huge numbers or extremely small number to scientific notations;

This was done to allow the calculator fit each values on its screen

$5.31 * 10^{37}$ is such a big number that it'll require the calculator to display it using scientific notations;

So, basically we have to convert $5.31 * 10^{37}$ to scientific notaton;

This is achieved by replacing $*10^{37}$ with $E37$

So, $5.31 * 10^{37}$ is equivalent to $5.31E37$

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3 years ago

The given amount converted to units?

Alisiya [41]

120 seconds is 2 * 60s
60s is 1 minute, so 2*60s = 2 minutes

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3 years ago

Show that every triangle formed by the coordinate axes and a tangent line to y = 1/x ( for x > 0)

vfiekz [6]

Answer:

Step-by-step explanation:

given a point $(x_0,y_0)$ the equation of a line with slope m that passes through the given point is

$y-y_0 = m(x-x_0)$ or equivalently

$y = mx+(y_0-mx_0)$ .

Recall that a line of the form $y=mx+b$ , the y intercept is b and the x intercept is $\frac{-b}{m}$ .

So, in our case, the y intercept is $(y_0-mx_0)$ and the x intercept is $\frac{mx_0-y_0}{m}$ .

In our case, we know that the line is tangent to the graph of 1/x. So consider a point over the graph $(x_0,\frac{1}{x_0})$ . Which means that $y_0=\frac{1}{x_0}$

The slope of the tangent line is given by the derivative of the function evaluated at $x_0$ . Using the properties of derivatives, we get

$y' = \frac{-1}{x^2}$ . So evaluated at $x_0$ we get $m = \frac{-1}{x_0^2}$

Replacing the values in our previous findings we get that the y intercept is

$(y_0-mx_0) = (\frac{1}{x_0}-(\frac{-1}{x_0^2}x_0)) = \frac{2}{x_0}$

The x intercept is

$\frac{mx_0-y_0}{m} = \frac{\frac{-1}{x_0^2}x_0-\frac{1}{x_0}}{\frac{-1}{x_0^2}} = 2x_0$

The triangle in consideration has height $\frac{2}{x_0}$ and base $2x_0$ . So the area is

$\frac{1}{2}\frac{2}{x_0}\cdot 2x_0=2$

So regardless of the point we take on the graph, the area of the triangle is always 2.

6 0

3 years ago

What is the solution to the system of equations? y = 1/3x-10 2x + y = 4

ladessa [460]

Answer: x = 6, y = -8

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3 years ago

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