Answer:A
Step-by-step explanation: Add the 1s first, you get 3, then add 3/8 and 5/8 and you Get 1. 3 +1 is 4 plus the remainder of 1/8
Answer:
Probability of missing two passes in a row is 0.08.
Step-by-step explanation:
Event E = A football player misses twice in a row.
P(E) = ?
Event X = Football player misses the first pass
P(X) = 0.4
Event Y = Football player misses just after he first miss
P(Y) = 0.2
Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:
P(E) = P(X).P(Y)
P(E) = 0.4*0.2
P(E) = 0.08
Answer:
1-a2
1-5x2
-4x2= -8
Step-by-step explanation: