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Rina8888 [55]
3 years ago
11

Which of the following elements is an Alkali Metal?

Chemistry
1 answer:
Viktor [21]3 years ago
8 0
Lithium is the Alkali metal



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Identify the best practices when storing and using drying agents in the lab.
IrinaVladis [17]

Answer:

A. Close the drying agent container whenever it is not in active use.

C. Wrap the lid of the drying agent container with tape for storage.

Explanation:

Drying agents also known as desiccants are used in pharmaceutical, food and other manufacturing to keep substances dry. These drying agents are anhydrous and hygroscopic. The right usage of these products requires that they are always stored in an air-tight container.

When they are to be removed from a container containing a solvent, they are to be separated by filtration or decanting.

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Which element is classified as a noble gas? (1) sulfur (3) argon (2) oxygen (4) nitrogen
valentina_108 [34]
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What is thermoplastics?
Vesnalui [34]

Answer:

A thermoplastic is any plastic material with a low melting point that becomes molten when heated, solid when cooled, and can be re-melted or molded after cooling. The curing process is completely reversible, and doing so will not compromise the material's physical integrity.

Credit to:https://www.fastradius.com/resources/thermoplastics-thermosets/#:~:text=A%20thermoplastic%20is%20any%20plastic,compromise%20the%20material's%20physical%20integrity.

Explanation:

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3 years ago
0.65 moles of O2 originally at 85°C is cooled
soldier1979 [14.2K]

Answer:

2.09 atm

Explanation:

We can solve this problem by using the equation of state for an ideal gas, which relates the pressure, the volume and the temperature of an ideal gas:

pV=nRT

where

p is the pressure of the gas

V is its volume

n is the number of moles

R is the gas constant

T is the absolute temperature

In this problem we have:

n = 0.65 mol is the number of moles of the gas

V = 8.0 L is the final volume of the gas

T=40C+273=313 K is the temperature of the gas

R=0.082 atm L mol^{-1} K^{-1} is the gas constant

Solving for p, we find the final pressure of the gas:

p=\frac{nRT}{V}=\frac{(0.65)(0.082)(313)}{8.0}=2.09 atm

8 0
4 years ago
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