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scoray [572]
3 years ago
14

Heellllloooooo plsss heellllpppp

Mathematics
1 answer:
MaRussiya [10]3 years ago
4 0
I think the answer is 720x^4
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Mei has 8 jars of soup. Each jar contains 300 milliliters of soup. What is the smallest pot Mei can use to heat all the soup.[PL
Kobotan [32]

Answer: A pot of 2400ml

Step-by-step explanation: Ok, mei has 8 jars, and each jar has 300ml of soup, so the total amount of soup is 8 times 300ml

N = 8*300ml = 2400ml

So the smallest pot that mei can use to heat the soup is a pot that has exactly that volume. 2400ml, (discarding the fact that the volume of the soup will change as it is heated up)

7 0
3 years ago
What is 101,949 rounded to the nearest hundred thousand?
kobusy [5.1K]
Well the answer is 103,000 because when you round it the 1 becomes a 2
5 0
3 years ago
Read 2 more answers
Diameter of a circle is something the length of its radius
Ede4ka [16]

the radius is half of the diameter, so d = 2r , or double the radius :)

3 0
3 years ago
helpppppp pleaseeeeee
Olin [163]

Answer:


Step-by-step explanation:

M' = (8,2)

A' = (7,6)

T' = (2,6)

H' =(3,2)

If this is a reflection across the y axis, then all that will change is the x value. You have to read that carefully to make sure you understand it.

Notice that T = (-2,6). All that happens is the the minus becomes a plus.

5 0
3 years ago
Log_c(A)=2<br> log_c(B)=5, <br> solve log_c(A^5B^3)
vlabodo [156]

We know that \log_a(bc)=\log_a(b)+\log_a(c).

Using this rule,

\log_c(A^5B^3)=\log_c(A^5)+\log_c(B^3).

We also know that \log_c(a^b)=b\log_c(a).

Using this rule,

\log_c(A^5)+\log_c(B^3)=5\log_c(A)+3\log_c(B)

Now we know that \log_c(A)=2,\log_c(B)=5 so,

5\cdot2+3\cdot5=10+15=\boxed{25}.

Hope this helps :)

3 0
2 years ago
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