The dimensions of the rectangle will be 6 inches and 12 inches.
<h3>What is the area of the rectangle?</h3>
Let L be the length and W be the width of the rectangle.
Then the area of the rectangle will be
Area of the rectangle = L × W square units
The length of a rectangular poster is 9 more inches than half its width.
L = W/2 + 9
The area of the poster is 72 square inches. Then we have
72 = L × W
72 = (W/2 + 9) × W
144 = (W + 18) × W
144 = W² + 18W
W² + 18W - 144 = 0
Then the factor of the equation will be
W² + 18W - 144 = 0
W² + 24W - 6W - 144 = 0
W(W + 24) - 6(W + 24) = 0
(W + 24)(W - 6) = 0
W = -24, 6
The width of the rectangle is 6 inches. Then the length of the rectangle will be
L = 6/2 + 9
L = 3 + 9
L = 12 inches
The dimensions of the rectangle will be 6 inches and 12 inches.
More about the area of the rectangle link is given below.
brainly.com/question/20693059
#SPJ1
Important Info
2 out of 10 flowers are daisys
she’s making 4 arrangements
2 (daisys) x 4 (arrangements) = 8 daisys to make 4 arrangements
The train Chug-a-Lug must be going 153.5 miles to match the same speed as Old Steamy so they can arrive at the station at the same time.
Answer:
19
Step-by-step explanation:
Assuming the function is x^2
let y = x^2
interchange x and y
x = y^2
y = sqrt x
so,
sqrt x is the inverse of x^2.
