Answer:
Step-by-step explanation:
908 - 105 A 0.00908 B 9.08 C 90.800,000 D 0.908
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The frustum can be considered as consisting of a square pyramid, less the
cut volume.
- The mass of the stand, is approximately 18.60905 kg
Reasons:
The given parameter of the frustum are;
The density of the frustum, ρ = 85 g/cm³
Height of pyramid, h = 9 cm
Side length of base = 10 cm
Height of frustum
By proportional shapes, the side length of the top of the frustum can be found as follows;
B₁ = 10², B₂ =
Therefore;
The volume of the stand, V ≈ 218.93 cm³
Mass = Volume × Density
∴ Mass of the stand, m = 218.93 cm³ × 85 g/cm³ = 18,609.05 grams = 18.60905 kg.
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Answer:
Step-by-step explanation:
step 1
In the right triangle ABC
Applying the Pythagoras Theorem fin the hypotenuse AC
substitute
step 2
we know that
If two figures are similar, then the ratio of its corresponding sides is equal
so
substitute and solve for CE
step 3
Find the length of segment AE
AE=AC+CE
substitute the values