Find the area of the figure shown: -35-105-70-no enough information.
2 answers:
You might be interested in
Answer:
see below
Step-by-step explanation:
The angle where chords cross is the average of the intercepted arcs. Here, that is ...
(37° +46°)/2 = (83°)/2 = 41.5°
Angle SUT is 41.5°.
_____
<em>Comment on the error</em>
The measure of an arc cannot be arbitrarily said to be the same as the angle where the chords cross. It will be the same if (a) the chords cross at the circle center, or (b) the opposite intercepted arc has the same measure. Neither of these conditions hold here.
A pyramid is regular if its base is a regular polygon, that is a polygon with equal sides and angle measures.
(and the lateral edges of the pyramid are also equal to each other)
Thus a regular rectangular pyramid is a regular pyramid with a square base, of side length say x.
The lateral faces are equilateral triangles of side length x.
The lateral surface area is 72 cm^2, thus the area of one face is 72/4=36/2=18 cm^2.
now we need to find x. Consider the picture attached, showing one lateral face of the pyramid.
by the Pythagorean theorem:
thus,
thus:
(cm^2)
but
is exactly the base area, since the base is a square of sidelength = x cm.
So, the total surface area = base area + lateral area =
cm^2
Answer: cm^2
(and the lateral edges of the pyramid are also equal to each other)
Thus a regular rectangular pyramid is a regular pyramid with a square base, of side length say x.
The lateral faces are equilateral triangles of side length x.
The lateral surface area is 72 cm^2, thus the area of one face is 72/4=36/2=18 cm^2.
now we need to find x. Consider the picture attached, showing one lateral face of the pyramid.
by the Pythagorean theorem:
thus,
thus:
but
So, the total surface area = base area + lateral area =
Answer: