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Kobotan [32]
3 years ago
7

Two different sizes of square metal duct are joined by a piece that is a frustum of a pyramid. Find the lateral surface area, if

the small end is square with one side of length 17 in. and the larger square end is of length 19 in. on one side with a slant height of 2 in.
Mathematics
1 answer:
Allisa [31]3 years ago
8 0

Answer:

288 in²

Step-by-step explanation:

The formula used to solve this question is :

Lateral Surface Area = s( P1 + P2)

Where s = slant height = 2 inches

P1 and P2 = Perimeter of the bases

Perimeter of base 1 = 4 × length of the end of the small square

4 × 17 inches = 68 inches

Perimeter of base 2 = 4 × length of the end of the large square

4 × 19 inches = 76 inches

Lateral Surface Area = 2 × (68 + 76)

= 2 × 144

= 288 in²

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Answer:

Gets smaller

Step-by-step explanation:

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                             s = Σ (  x - u ) / sqrt ( n )

Where, n : sample size

            u : Mean value

- So we see that standard deviation (s) is inversely proportional to square root of sample size (n).

- We can see that as sample size (n) increases the standard deviation (s) decreases.

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=6%5Csqrt%7B3%7D%2B2%281-%5Csqrt%7B27%7D%29%3D2" id="TexFormula1" title="6\sqrt{3}+2(1-\sqrt{27
skelet666 [1.2K]

Answer:

This is true.

Step-by-step explanation:

Step 1: see that √27 is the same as √3*3*3 and thus 3√3

Step 2: remove parenthesis so that 2(1-3√3) becomes 2 - 6√3

Step 3: observe that the equation now becomes 6√3 + 2 - 6√3 = 2

if you simplify any further, you are left with 0=0, which is true.

Comment if there is any step that requires more details...

3 0
3 years ago
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Step-by-step explanation:

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slavikrds [6]

Answer:

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Step-by-step explanation:

We are required to reduce the expression below to its simplest form

-\dfrac{7}{8}-\left(-\dfrac{5}{6}\right)

<u>STEP 1: </u>Remove the brackets

Take note that the product of same sign(- and -) will give you the addition sign.

-\dfrac{7}{8}-\left(-\dfrac{5}{6}\right)=-\dfrac{7}{8}+\dfrac{5}{6}

<u>STEP 2:</u> Find the Lowest Common Multiple of 8 and 6

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<u>STEP 3:</u> Use the LCM to Simplify

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