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Dmitrij [34]
3 years ago
10

The price of a buffet lunch is $14.80 per adult and $12 per children. William paid a total of $95.2 for a group of m adults and

n children. write an caution that would represent the situation.
Mathematics
2 answers:
lianna [129]3 years ago
5 0

Answer:

$14.80(m) + $12(n) = $95.2

Solved:

$14.80(4) + $12(3) = $95.2

Step-by-step explanation:

m represents Adults ($14.80m) | n represents Children ($12n)

4 Adults times $14.80 equals $59.2

3 Children times $12 equals $36

Add $36 and $59.2 and you get $95.2

Citrus2011 [14]3 years ago
5 0

Answer:

14.80m + 12n = 95.2

Step-by-step explanation:

1 adult = $14.80

so, m adults = $(14.80 x m) = $14.80m

1 child = $12

so, n children = $(12 x n) = $12n

Therefore: $14.80m + $12n = $95.2

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This is a modulus inequality.
First part: when (6x + 2) is positive
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Second part: when (6x + 2) is negative.

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