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Dmitrij [34]
3 years ago
10

The price of a buffet lunch is $14.80 per adult and $12 per children. William paid a total of $95.2 for a group of m adults and

n children. write an caution that would represent the situation.
Mathematics
2 answers:
lianna [129]3 years ago
5 0

Answer:

$14.80(m) + $12(n) = $95.2

Solved:

$14.80(4) + $12(3) = $95.2

Step-by-step explanation:

m represents Adults ($14.80m) | n represents Children ($12n)

4 Adults times $14.80 equals $59.2

3 Children times $12 equals $36

Add $36 and $59.2 and you get $95.2

Citrus2011 [14]3 years ago
5 0

Answer:

14.80m + 12n = 95.2

Step-by-step explanation:

1 adult = $14.80

so, m adults = $(14.80 x m) = $14.80m

1 child = $12

so, n children = $(12 x n) = $12n

Therefore: $14.80m + $12n = $95.2

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\hat{n} = \hat{r_{u}} \times \hat{r_{v}}\\r_{u}=\frac{\partial r}{\partial u}\\r_{v}=\frac{\partial r}{\partial v}

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Normal vector  tangent to plane is given by:

r_{u} \times r_{v} =det\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\cos(v)&sin(v)&0\\-usin(v)&ucos(v)&1\end{array}\right]

Expanding with first row

\hat{n} = \hat{i} \begin{vmatrix} sin(v)&0\\ucos(v) &1\end{vmatrix}- \hat{j} \begin{vmatrix} cos(v)&0\\-usin(v) &1\end{vmatrix}+\hat{k} \begin{vmatrix} cos(v)&sin(v)\\-usin(v) &ucos(v)\end{vmatrix}\\\hat{n}=sin(v)\hat{i}-cos(v)\hat{j}+u(cos^{2}v+sin^{2}v)\hat{k}\\\hat{n}=sin(v)\hat{i}-cos(v)\hat{j}+u\hat{k}\\

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                  =\frac{\sqrt{3} }{2}\hat{i}-\frac{1}{2}\hat{j}+\hat{k} ---(2)

at u=5, v =π/3 (1) becomes,

                 r(5, \frac{\pi}{3})=5 cos (\frac{\pi}{3})\hat{i}+5sin (\frac{\pi}{3})\hat{j}+\frac{\pi}{3}\hat{k}

                r(5, \frac{\pi}{3})=5(\frac{1}{2})\hat{i}+5 (\frac{\sqrt{3}}{2})\hat{j}+\frac{\pi}{3}\hat{k}

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