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Elena L [17]
3 years ago
12

Ken used 3/4 of his wrapping paper. If he used 12 feet how much wrapping paper did he use

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
8 0

Answer: If Ken used 12 feet of wrapping paper, 3/4 then he would have had 16 ft of wrapping paper before he started wrapping

Step-by-step explanation:

12 divided by 3 is 4 giving us the equation 4/4 equals 4 x 4

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  parallelogram

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Read 2 more answers
so the volume is that of a cylinder V=hpir^2 h=8 r=2 pi=3.141592 V=8*3.141592*2^2 V=8*3.141592*4 V=32*3.141592 V=100.530944 roun
Mashcka [7]
Volume=(height)(pi)(radius^2)
Volume=(8)(3.141592)(2^2)
V=(8)(4)(3.141592)
V=(32)(3.141592)
V=100.530944

7 0
3 years ago
Mjnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnn
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I don't know what this is supposed to mean, but thanks for the free points! ;)

7 0
3 years ago
What’s the answer? Because am having a hard time with this math problem.
Studentka2010 [4]

9514 1404 393

Answer:

  34.5 square meters

Step-by-step explanation:

We assume you want to find the area of the shaded region. (The actual question is not visible here.)

The area of the triangle (including the rectangle) is given by the formula ...

  A = 1/2bh

The figure shows the base of the triangle is 11 m, and the height is 1+5+3 = 9 m. So, the triangle area is ...

  A = (1/2)(11 m)(9 m) = 49.5 m^2

The rectangle area is the product of its length and width:

  A = LW

The figure shows the rectangle is 5 m high and 3 m wide, so its area is ...

  A = (5 m)(3 m) = 15 m^2

The shaded area is the difference between the triangle area and the rectangle area:

  shaded area = 49.5 m^2 - 15 m^2 = 34.5 m^2

The shaded region has an area of 34.5 square meters.

7 0
3 years ago
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