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Elena L [17]
3 years ago
12

Ken used 3/4 of his wrapping paper. If he used 12 feet how much wrapping paper did he use

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
8 0

Answer: If Ken used 12 feet of wrapping paper, 3/4 then he would have had 16 ft of wrapping paper before he started wrapping

Step-by-step explanation:

12 divided by 3 is 4 giving us the equation 4/4 equals 4 x 4

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Identify the slope as positive, negative, zero or undefined
slavikrds [6]

Answer:

Zero

Step-by-step explanation:

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3 years ago
A milligram is what fraction of a kilogram
pishuonlain [190]
The answer is 1/1000000
4 0
3 years ago
baseball card come in packs of a dozen 12 cards matt has 132 baseballcards.how many packs of baseball cards did he buy i need he
Hunter-Best [27]
Well let's see first we have to divide
132 divided by 12 is 11
Now to check and prove your answer we should use the multiplication.
11 times 12 is 132.
So now you have a solid answer with proof behind it.
If u need a sentence you might want it to go something like this;
Matt brought 11 packs of baseball cards since 132 divided by 12 is 11. 12 times 11 is 132 cards.
Hope I helped!
5 0
3 years ago
Read 2 more answers
The figure the Floor Plan of a balcony ,it consists of △ABC and semi-circle ,
ivanzaharov [21]

Step-by-step explanation:

(a) In right triangle ABC,

AC^2 =AB^2 +BC^2  \\  =  {12}^{2} +  {5}^{2}   \\  = 144 + 25 \\  = 169 \\  AC =  \sqrt{169}  \\  \therefore \: AC =  13\: m \\  \\ AC \: is \: the \: diameter \: of \: semicircle \\  \therefore \: r =  \frac{1}{2} \times  AC = \frac{1}{2} \times 13 = 6.5 \: m \\  Circumference \:of \:semi-circle \\ C = \pi \: r = 3.14 \times 6.5 = 20.41 \:m\:

Perimeter of Balcony = 12 + 5 + 20.41 = 37.41 m

(b) Area of balcony

=\frac{1}{2}\times 12\times 5+\frac{1}{2} \pi r^2 \\\\=\times 6\times 5+\frac{1}{2} \times 3.14\times (6.5)^2 \\\\=30+\frac{1}{2} \times 3.14\times42.25\\\\= 30+\frac{1}{2} \times 132.665\\\\= 30 + 66.3325\\\\= 96.3325 \:m^2 \\\\\approx 96. 33\:m^2

8 0
4 years ago
For what values of x and y must ABCD be a parallelogram?
n200080 [17]
<h2>x^{\circ}=21^{\circ} \ and \ y^{\circ}=39^{\circ}</h2>

Step-by-step explanation:

We know that vertically opposite angles of a parallelogram are equal .

\angle ABC =\angle ADC\ and \ \angle BAD = \angle DAC

⇒3x^{\circ}=(4x-21)^{\circ} \ and \ 3y^{\circ}=(y+78)^{\circ}

⇒3x^{\circ}-4x^{\circ}=-21^{\circ} \ and \ 3y^{\circ}-y^{\circ}=78^{\circ}

⇒-x^{\circ}=-21^{\circ} \ and \ 2y^{\circ}=78^{\circ}

⇒x^{\circ}=21^{\circ} \ and \ y^{\circ}=39^{\circ}

7 0
4 years ago
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