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3 years ago

If the team needs 3 beams and 6 channels will the grant cover the cost(grant is 75.00)

Mathematics

2 answers:

Nadusha1986 [10]3 years ago

8 0

Answer:

Ilan lahat Ang kabuuang bilang ng mga nakalarawang bagay

andrew-mc [135]3 years ago

3 0

What is the cost for the beams and channels?

Once you know what beams cost fill them in this equation as “b” and channels as “c”:
3b+6c<75

If this is true, the grant will cover the cost. If this is false, the grant will not cover the cost.

Hope this helps! You can comment if you still have a hard time and I’ll try to help. Pls mark brainliest if it helps.

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Plz help I need to understand and I don’t

aliina [53]

Answer:

B. $108 \: {in}^{2}$

Step-by-step explanation:

Total surface area of the square pyramid

= 4 times the area of one triangle + Area of square

$= 4 \times \frac{1}{2} \times 6 \times 6 + {6}^{2} \\ \\ = 72 + 36 \\ \\ = 108 \: {in}^{2}$

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3 years ago

Least common multiple of <br> 42, 45, 60 and 175

Harlamova29_29 [7]

Answer: The answer is 6300

Step-by-step explanation:

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3 years ago

Find the area of triangle jkl above if the vertices are j(2,2), k(3,5), and L(6,2)

tankabanditka [31]

Answer:

$Area=6\:units^2$

Step-by-step explanation:

Given the vertices $(x_1,y_1)=J(2,2)$ , $(x_2,y_2)=K(3,5)$ and

$(x_3,y_3)=L(6,2)$ . The area of triangle JKL is given by:

$Area=\frac{1}{2}|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|$

We substitute the values to get:

$Area=\frac{1}{2}|2(5-2)+3(2-2)+6(2-5)|$

This simplifies to

$Area=\frac{1}{2}|2(3)+3(0)+6(-3)|$

$Area=\frac{1}{2}|6+0-18|$

$Area=\frac{1}{2}|-12|$

$Area=\frac{1}{2}*12$

$Area=6\:units^2$

3 0

4 years ago

Can 6,12, and 18 make a triangle?

OverLord2011 [107]

By definition, 3 side lengths are a triangle if any 2 side lengths add up to be greater than the third.

We can already see that the side lengths 6 and 12 will add up to a value of 18, which is equal to the last side length, meaning that the three values are not a triangle.

$a=6$