This is not my answer I found it from another brainly
From the beginning we know we are dealing with two different rates. Distance is equal to (Speed X Time). We have two different speeds though. We will call the min speed = x and the max speed = y. With those two ideas in place we can make two equations for both Tony and Rae.
Tony:
2x+3.5y=355
Rae:
2x+3y=320
Now you can solve the equations by subtracting Rae's equation from Tony's
.5y=35 solve for y and you get 70
Now plug that y value back into either equation and you can solve for x. I'll use Rae's distance:
2x+3(70)=320
x=55
Answer:
1. y=(x+3)^3. Zero: x=-3 multiplicity 3.
2. y=(x-2)^2 (x-1). Zeros: x=2 multiplicity 2; x=1 multiplicity 1.
3. y=(2x+3)(x-1)^2. Zeros: x=-3/2 multiplicity 1; x=1 multiplicity 2.
Step-by-step explanation:
1. y=(x+3)^3
![y=0\\ (x+3)^3=0\\ \sqrt[3]{(x+3)^3}=\sqrt[3]{0}\\ x+3=0\\ x+3-3=0-3\\ x=-3](https://tex.z-dn.net/?f=y%3D0%5C%5C%20%28x%2B3%29%5E3%3D0%5C%5C%20%5Csqrt%5B3%5D%7B%28x%2B3%29%5E3%7D%3D%5Csqrt%5B3%5D%7B0%7D%5C%5C%20x%2B3%3D0%5C%5C%20x%2B3-3%3D0-3%5C%5C%20x%3D-3)
Zero: x=-3 multiplicity 3.
2. y=(x-2)^2 (x-1)
Zeros: x=2 multiplicity 2; x=1 multiplicity 1
3. y=(2x+3)(x-1)^2
Zeros: x=-3/2 multiplicity 1; x=1 multiplicity 2.
Answer:
243/4(x^12)
Step-by-step explanation:
81x^12 x 3/4 = 243/4(x^12)
4.312, 4.316, 4.32, 4.5
I hope this helps ^W^ have a great day!
