Answer:
sorry I cannot understand that
Distinct prime factors are factors that can not be reduced any further.... Such factors are like 3,5, and 7.
Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
P(brown) = 12% = 0.12
P(Yellow) = 15% = 0.15
P(Red) = 12% = 0.12
P(blue) = 23% = 0.23
P(orange) = 23% = 0.23
P(green) = 15% = 0.15
A.) Compute the probability that a randomly selected peanut M&M is not yellow.
P(not yellow) = P(Yellow)' = 1 - P(Yellow) = 1 - 0.15 = 0.85
B.) Compute the probability that a randomly selected peanut M&M is brown or red.
P(Brown) or P(Red) :
0.12 + 0.12 = 0.24
C.) Compute the probability that three randomly selected peanut M&M’s are all brown.
P(brown) * P(brown) * P(brown)
0.12 * 0.12 * 0.12 =0.001728
D.) If you randomly select three peanut M&M’s, compute that probability that none of them are blue.
P(3 blue)' = 1 - P(3 blue)
P(3 blue) = 0.23 * 0.23 * 0.23 = 0.012167
1 - P(3 blue) = 1 - 0.012167 = 0.987833
If you randomly select three peanut M&M’s, compute that probability that at least one of them is blue.
P(1 blue) + p(2 blue) + p(3 blue)
(0.23) + (0.23*0.23) + (0.23*0.23*0.23)
0.23 + 0.0529 + 0.012167
= 0.295067
Answer:
Step-by-step explanation:
Start box
180 = 89+42+x
180-89-42=x
49 = x
2nd box
180 = 84+58+x
180-84-58=x
38 = x
3rd box
180=74+2x
180-74=2x
106/2 = x
53 = x
4th box
180=102+2x
180-102=2x
78/2 = x
39 = x
4th box
180 = 73+81 +x
180-73-81=x
26 = x
5th box
180=2*54+x
180 - 2*54 = x
72 = x
6th box
180=62-2x
180-62=2x
118=2x
118/2=x
59 = x
7th box
180 = 2*68 + x
180-2*68=x
44 = x
If you have listed the answer choices properly, none is correct. The orthocenter is (-2, 12).
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See the attached figure.
