x-coordinates for the maximum points in any function f(x) by f'(x) =0 would be x = π/2 and x= 3π/2.
<h3>How to obtain the maximum value of a function?</h3>
To find the maximum of a continuous and twice differentiable function f(x), we can firstly differentiate it with respect to x and equating it to 0 will give us critical points.
we want to find x-coordinates for the maximum points in any function f(x) by f'(x) =0
Given f(x)= 4cos(2x -π)
In general 
from x = 0 to x = 2π :
when k =0 then x = π/2
when k =1 then x= π
when k =2 then x= 3π/2
when k =3 then x=2π
Thus, X-coordinates of maximum points are x = π/2 and x= 3π/2
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Answer: 8473938057509178444444
Step-by-step explanation:
Answer: F. Parameter, because the data set of all 2000 students in a high school is a population.
Step-by-step explanation:
Parameters is a variable or measure that is calculated from the entire population of data while a statistic is done from a sample of the data.
The question notes that the poll was done on <u>all 2,000</u> students in a high school. This means that the poll is a Parameter because it was done on the entire population of the high school.
The answer is 194 because you multiply 59 and 500 and then 38 and 500 you then get 29,500 plus 19,000 divided by 250 you add the two together and get 48,500 divided by 250 and end up with 194
