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Sindrei [870]
2 years ago
11

What are the x-coordinates for the maximum points in the function f(x) = 4 cos(2x − π) from x = 0 to x = 2π? (1 point) a x = 3 p

i over 2 , x = π b x =
Mathematics
1 answer:
Ratling [72]2 years ago
4 0

x-coordinates for the maximum points in any  function  f(x) by f'(x) =0 would be  x = π/2 and x= 3π/2.

<h3>How to obtain the maximum value of a function?</h3>

To find the maximum of a continuous and twice differentiable function f(x), we can firstly differentiate it with respect to x and equating it to 0 will give us critical points.

we want to find x-coordinates for the maximum points in any  function  f(x) by f'(x) =0

Given f(x)= 4cos(2x -π)

f'(x) = 0\\- 4sin(2x -\pi ) =0\\\\sin (2x -\pi ) =0 \\2x -\pi  = k\pi ...  k in Z

In general  x=(k+1)\pi /2

from x = 0 to x = 2π :

when k =0  then  x = π/2

when k =1  then x= π

when k =2  then x= 3π/2

when k =3  then x=2π

Thus, X-coordinates of maximum points are  x = π/2 and x= 3π/2

Learn more about maximum of a function here:

brainly.com/question/13333267

#SPJ4

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