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Papessa [141]
3 years ago
7

True or false? Help please

Mathematics
1 answer:
Leokris [45]3 years ago
7 0

Answer:

but I don't know,I hope you understand

Step-by-step explanation:

i hope you understand ☺️

if who one knows please answer her/his question

thank you

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The number of tickets sold for a concert during each hour ,x, of the first 10hours the tickets were in sale is given by g(x)=x^3
Mashutka [201]

The number in tickets sold A)107

8 0
4 years ago
Which line represents the direct variation equation y= 1/2x?
sleet_krkn [62]

Answer:

Answer Expert Verified y = (slope) x + (y-intercept) . Right away, you know that this line goes through the origin ...

6 0
3 years ago
Solve for x : 1/a+b+x =1/a+1/b+1/x
ANTONII [103]

Answer:

  x ∈ {-a, -b}

Step-by-step explanation:

  1/(a+b+x) = 1/a +1/b +1/x . . . . given

  abx = bx(a+b+x) +ax(a+b+x) +ab(a+b+x) . . . . multiply by abx(a+b+x)

  (a+b)x^2 +(a+b)^2x +ab(a+b) = 0 . . . . . subtract abx

  x^2 + (a+b)x +ab = 0 . . . . . divide by (a+b)

This is a quadratic equation in x. It will have two solutions, as given by the quadratic formula.

  x = (-(a+b) ±√((a+b)^2 -4(1)(ab))/(2(1)) = (-(a+b) ± |a -b|)/2

Without loss of generality, we can assume a ≥ b, so |a -b| ≥ 0. Then ...

  x = (-a -b -a +b)/2 = -a

  x = (-a -b +a -b)/2 = -b

There are two solutions: x ∈ {-a, -b}.

4 0
3 years ago
A.
vladimir1956 [14]
The answer is C: x < -2
The fact that it is less than -2 is shown by the open circle on -2, and the arrow pointing to the left. An open circle means that the number cannot be included (which is why it can't be "less than or equal to," but instead is just "less than."), and the line pointing to the left means that your variable is specifically less than the number circled.
3 0
3 years ago
Helppppppppppppppppp
nasty-shy [4]

Answer:

Bowler World: C = 1.1 g + 5

Lucky Spares: C = 1.5 g + 3

The cost is the same for 5 games, The cost is $10.50

Step-by-step explanation:

5+1.1(5) = 5+5.5=10.50

3+1.5(5) = 3+7.5=10.50

Hopefully, this helped :)

3 0
3 years ago
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