Answer:
6
Step-by-step explanation:
7 x 6 = 42 + 9 = 51 + 54 = 105 + 75= 180
-4x+2=9 would be the answer for this equation
Answer:
D
Step-by-step explanation:
i did it with eliminating choices
Answer:
Correct option is
B
90
∘
,90
∘
,90
∘
Let AB and CD be two lines Intersecting at O, such that, ∠AOD=90
∘
Now, ∠AOD=∠COB=90
∘
(Vertically opposite angles)
⟹∠AOD+∠DOB=180
o
(Angles on a straight line)
⟹90+∠DOB=180
o
∠DOB=90
∘
∠DOB=∠AOC=90
∘
(Vertically opposite angles)
Thus, all angles are 90
∘
.
Answer:
see the attachment
Step-by-step explanation:
We assume that the question is interested in the probability that a randomly chosen class is a Friday class with a lab experiment (2/15). That is somewhat different from the probability that a lab experiment is conducted on a Friday (2/3).
Based on our assumption, we want to create a simulation that includes a 1/5 chance of the day being a Friday, along with a 2/3 chance that the class has a lab experiment on whatever day it is.
That simulation can consist of choosing 1 of 5 differently-colored marbles, and rolling a 6-sided die with 2/3 of the numbers being designated as representing a lab-experiment day. (The marble must be replaced and the marbles stirred for the next trial.) For our purpose, we can designate the yellow marble as "Friday", and numbers greater than 2 as "lab-experiment".
The simulation of 70 different choices of a random class is shown in the attachment.
_____
<em>Comment on the question</em>
IMO, the use of <em>70 trials</em> is coincidentally the same number as the first <em>70 days</em> of school. The calendar is deterministic, so there will be exactly 14 Fridays in that period. If, in 70 draws, you get 16 yellow marbles, you cannot say, "the probability of a Friday is 16/70." You need to be very careful to properly state the question you're trying to answer.