Answer:
2nd, 3rd and 6th are the solutions
Step-by-step explanation:
Answer:


Step-by-step explanation:
<u>Second-Degree Equation</u>
The second-degree equation or quadratic equation has the general form

where a is non-zero.
There are many methods to solve the equation, one of the most-used is by using the solver formula:

The equation of the question has the values: a=1, b=2, c=4, thus the values of x are


Since the square root has a negative argument, both solutions for x are imaginary or complex. Simplifying the radical

The solutions are


Answer:
7
Step-by-step explanation: