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3 years ago

Please help See the picture Line A , B , C OR D ? Help

Mathematics

1 answer:

Vlada [557]3 years ago

6 0

Answer:

option b 3x+6y=-57

-3x-6y=57

Step-by-step explanation:

please mark me as brainlest

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Rewrite in Polar Form....<br> x^(2)+y^(2)-6y-8=0

skad [1K]

$\bf x^2+y^2-6y-8=0\qquad 
\begin{cases}
x^2+y^2=r^2\\\\
y=rsin(\theta)
\end{cases}\implies r^2-6rsin(\theta)=8
\\\\\\
\textit{now, we do some grouping}\implies [r^2-6rsin(\theta)]=8
\\\\\\\
[r^2-6rsin(\theta)+\boxed{?}^2]=8\impliedby 
\begin{array}{llll}
\textit{so we need a value there to make}\\
\textit{a perfect square trinomial}
\end{array}$

$\bf 6rsin(\theta)\iff 2\cdot r\cdot \boxed{3\cdot sin(\theta)}\impliedby \textit{so there}
\\\\\\
\textit{now, bear in mind we're just borrowing from zero, 0}
\\\\
\textit{so if we add, \underline{whatever}, we also have to subtract \underline{whatever}}$

$\bf [r^2-6rsin(\theta)\underline{+[3sin(\theta)]^2}]\quad \underline{-[3sin(\theta)]^2}=8\\\\
\left. \qquad \right.\uparrow \\
\textit{so-called "completing the square"}
\\\\\\\
[r-3sin(\theta)]^2=8+[3sin(\theta)]^2\implies [r-3sin(\theta)]^2=8+9sin^2(\theta)
\\\\\\
r-3sin(\theta)=\sqrt{8+9sin^2(\theta)}\implies r=\sqrt{8+9sin^2(\theta)}+3sin(\theta)$

3 0

3 years ago

The range of a set of data is 15, and the interquartile range of the same set is 12. Which of the following statements is probab

antiseptic1488 [7]

The answer would be (The two ranges are close together, so there are probably no outliers in this set. )

6 0

3 years ago

What is the answer??

eduard

If the bikes original price was $112.99...
and it's 75% off you have to multiply the original price by the percentage thats left which is 25%...
$112.99×.25%=28.25
ANSWER: b)28.25

6 0

3 years ago

PLEASE HELP ITS A TIMED QUIZ IM DESPERATE ILL GIVE U BRAINLIEST AND A THANKS PLEASE

den301095 [7]

Answer:

2000 = 600 + 2/5x ; 3500 ft

How To Solve:

2000 = 600 + 2/5x

Combine multiplied terms into a single fraction

2000 = 600 + 2/5x

2000 = 600 + 2x/5

Subtract 600 from both sides of the equation

2000 = 600 + 2x/5

2000 - 600 = 600 + 2x/5 - 600

Simplify

Subtract the numbers

1400 = 600 + 2x/5 − 600

Subtract the numbers

1400 = 2x/5

Solution

X = 3500

7 0

3 years ago

A/ab-bsquare + b/ab-asquare?

lord [1]

Answer:

$\dfrac{(a+b)}{ab}$

Step-by-step explanation:

The given expression is :

$\dfrac{a}{ab-b^2}+\dfrac{b}{ab-a^2}$

It can be solved as follows :

$\dfrac{a}{ab-b^2}+\dfrac{b}{ab-a^2}=\dfrac{a}{b(a-b)}+\dfrac{b}{a(b-a)}\\\\=\dfrac{a}{b(a-b)}+\dfrac{b}{-a(-b+a)}\\\\=\dfrac{1}{a-b}(\dfrac{a}{b}-\dfrac{b}{a})\\\\=\dfrac{a^2-b^2}{ab(a-b)}\\\\=\dfrac{(a-b)(a+b)}{ab(a-b)}\\\\=\dfrac{(a+b)}{ab}$

So, the solution of the given expression is equal to $\dfrac{(a+b)}{ab}$ .

7 0

3 years ago