Answer:
a)
y = 0.3035 + 0.0082x
b)
0.6315 mm
c)
x = 23.9634 °C
Step-by-step explanation:
a. Compute the least-squares line for predicting warping from temperature. Round the answers to four decimal places.
We need to find an equation of the form
y = b + mx
where m is the slope and b the Y-intercept.
The slope m can be computed with the formula
Replacing the values in our formula (we will round at the end of the calculations)
the Y-intercept b is computed with the formula
therefore we have
and the least-squares line rounded to 4 decimals would be
y = 0.3035 + 0.0082x
b. Predict the warping at a temperature of 40°C. Round the answer to three decimal places.
We simply replace x with 40 to get
y = 0.3035 + 0.0082*40 = 0.6315 mm
c. At what temperature will we predict the warping to be 0.5 mm? Round the answer to two decimal places
Here, we replace y with 0.5 and solve for x
0.5 = 0.3035 + 0.0082x ===> x = (0.5-0.3035)/0.0082 ===>
x = 23.9634 °C
First distribute the 2(2+4x)
3x-4+4+8x
then just combine like terms.
8+11x
therefore
3x-4+2(2+4x)=8+11x<span />
Answer:
h = 1000 / (3.14)(r²)
Step-by-step explanation:
Given in the question,
volume of cylinder = 1000 inches³
Formula to use
V = πr²h
where V = volume
π = 3.14
r = radius
h = height
1000 = (3.14)(r²)(h)
h = 1000 / (3.14)(r²)
The answer A.the solution is (5,-2) definitely works because 5+-2=3 and 5--2=7 not sure if there's infinite number of solutions tho
The first example has students building upon the previous lesson by applying the scale factor to find missing dimensions. This leads into a discussion of whether this method is the most efficient and whether they could find another approach that would be simpler, as demonstrated in Example 2. Guide students to record responses and additional work in their student materials.
§ How can we use the scale factor to write an equation relating the scale drawing lengths to the actual lengths?
!
ú Thescalefactoristheconstantofproportionality,ortheintheequation=or=!oreven=
MP.2 ! whereistheactuallength,isthescaledrawinglength,andisthevalueoftheratioofthe drawing length to the corresponding actual length.
§ How can we use the scale factor to determine the actual measurements?
ú Divideeachdrawinglength,,bythescalefactor,,tofindtheactualmeasurement,x.Thisis
! illustrated by the equation = !.
§ How can we reconsider finding an actual length without dividing?
ú We can let the scale drawing be the first image and the actual picture be the second image. We can calculate the scale factor that relates the given scale drawing length, , to the actual length,. If the actual picture is an enlargement from the scale drawing, then the scale factor is greater than one or
> 1. If the actual picture is a reduction from the scale drawing, then the scale factor is less than one or < 1.
Scaffolding:
A reduction has a scale factor less than 1, and an enlargement has a scale factor greater than 1.
Lesson 18: Computing Actual Lengths from a Scale Drawing.
