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2 years ago

4√90 in simplest radical form.

Mathematics

1 answer:

eduard2 years ago

7 0

Answer:

It’s an irrational number. 3.08007288, just round it to the nearest whole number and you’ll get 3.

You might be interested in

A. What is the explicit definition for this sequence?<br><br>b. How far does she run on day 19?

creativ13 [48]

Answer:

(a) $a_n=1+\frac{1}{6}(n-1)$

(b) 4 miles

Step-by-step explanation:

Given:

The sequence of run is an arithmetic sequence.

Miles traveled on day 1 = 1 mile

Miles traveled on day 7 = 2 miles

(a).

Explicit formula for an arithmetic sequence is given as:

$a_n=a_1+(n-1)d\\a_n\to n^{th}\ term\\a_1\to first\ term\\n\to number\ of\ terms\\d\to \textrm{common difference}$

Here, $a_1=1,a_7=2$

So,

$a_7=a_1+(7-1)d\\2=1+6d\\6d=2-1\\d=\frac{1}{6}$

Therefore, the explicit definition of the above sequence is given as:

$a_n=1+\frac{1}{6}(n-1)$

Where, $a_n$ is the miles covered on $n^{th}$ day.

(b)

In order to find the distance covered by her on day 19, we plug in 19 for n in the above formula. This gives,

$a_{19}=1+\frac{1}{6}(19-1)\\\\a_{19}=1+\frac{1}{6}(18)\\\\a_{19}=1+3=4\ mi$

Therefore, the number of miles covered by her on day 19 is 4 miles.

3 0

2 years ago

Select the relations that are functions.

Arlecino [84]

Answer:

Depending on how the input of each function defined,

The first choice $\left\lbrace(a, 1),\, (6, 1), \, (C, 1)\right\rbrace$ ,
The third choice $\left\lbrace(1, a),\, (2, a), \, (3, a)\right\rbrace$
The fourth choice $\left\lbrace(a, a),\, (b, b), \, (c, c)\right\rbrace$

might be functions.

Step-by-step explanation:

A function between two sets (domain and range) should

be defined for all elements in the domain, and
map each element from the domain to exactly one element in the range.

The second choice can't be a function since the element $a$ from the domain is mapped to more than one element in the range.

Keep in mind that a function should be defined for all elements in its domain. For the first relation to be a function, its domain needs to be $\lbrace a,\, 6, \, C\rbrace$ . Similarly, the domain for the third and fourth relations should be $\lbrace 1,\, 2, \, 3\rbrace$ and $\lbrace a,\, b, \, c\rbrace$