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anastassius [24]
3 years ago
10

Based on the scatterplot and the value of the correlation coefficient, it would make sense to test the significance of this obse

rved linear relationship between latitude and melanoma mortality rate. The appropriate hypotheses are:
a. H0: melanoma mortality rate is related to latitude
Ha: melanoma mortality rate is not related to latitude
b. H0: melanoma mortality rate is not related to latitude
Ha: melanoma mortality rate is related to latitude
c. H0: melanoma mortality rate is linearly related to latitude
Ha: melanoma mortality rate is not linearly related to latitude
d. H0: melanoma mortality rate is not linearly related to latitude
Ha: melanoma mortality rate is linearly related to latitude
Mathematics
1 answer:
Aleks [24]3 years ago
5 0

Answer:

d. H0: melanoma mortality rate is not linearly related to latitude

   Ha: melanoma mortality rate is linearly related to latitude

Step-by-step explanation:

The linear regression equation is

y=α+βx where α=intercept and β=slope.

β=slope demonstrates the change in dependent variable due to unit change in independent variable.

If the slope is zero then we can say that Y and X are not linearly related.

Thus, the hypothesis for testing significance of linear relationship two variables can be written as

Null hypothesis: The two variables are not linearly related i.e. β=0

Alternative hypothesis : The two variables are linearly related i.e. β≠0.

Thus, in the given scenario the hypothesis are

H0: melanoma mortality rate is not linearly related to latitude

Ha: melanoma mortality rate is linearly related to latitude.

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kompoz [17]

Answer:

x < -4

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Equality Properties

Step-by-step explanation:

<u>Step 1: Define inequality</u>

-16x - 10 > 14 - 10x

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Add 16x to both sides:                    -10 > 14 + 6x
  2. Subtract 14 on both sides:              -24 > 6x
  3. Divide 6 on both sides:                   -4 > x
  4. Rewrite:                                            x < -4

Here we see that any value <em>x</em> that is less than -4 would work as a solution.

4 0
2 years ago
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PLEASE ANSWER ASAP!! e)What is the measure of ∠I? Explain
Zina [86]

Answer:

60^{\circ}

Step-by-step explanation:

From the given figure it is clear that the stop board is a regular hexagon and ∠I is an exterior angle of the regular hexagon.

Exterior angle of a regular polygon with n sides =\dfrac{360^{\circ}}{n}

In a regular hexagon number of sides: n =6

Exterior angle of a regular hexagon =\dfrac{360^{\circ}}{6}=60^{\circ}

Since ∠I is an exterior angle of the regular hexagon, therefore, \angle I=60^{\circ}.

4 0
3 years ago
67,396 divided by 123
ruslelena [56]
547.9 is the answer to this
8 0
3 years ago
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F(x)=x^3+10x^2+31x+30
Colt1911 [192]

The factors of the given polynomial will be ( x + 2 ), ( x + 5 ) and ( x + 3 ).

<h3>What is an expression?</h3>

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication and division.

The given expression will be solved as:-

f(x) = x³ + 10x² + 31x + 30

f(x) = ( x³ + 7x² + 10x + 3x² + 21x + 30

f(x) = ( x² + 7x + 10 ) ( (x + 3 )

f(x) = ( x²+ 5x + 2x + 10 ) ( x + 3 )

f(x) =[ x ( x+ 5 ) +2 ( x+ 5) ] ( x + 3 )

f(x) = ( x + 5 ) ( x + 2 ) ( x + 3 )

Therefore factors of the given polynomial will be ( x + 2 ), ( x + 5 ) and ( x + 3 ).

To know more about Expression follow

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5 0
2 years ago
A sample of radium has a weight of 1.5 mg and a half-life of approximately 6 years.
pogonyaev

Answer:

0.75 mg

Step-by-step explanation:

From the question given above the following data were obtained:

Original amount (N₀) = 1.5 mg

Half-life (t₁/₂) = 6 years

Time (t) = 6 years

Amount remaining (N) =.?

Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:

Half-life (t₁/₂) = 6 years

Time (t) = 6 years

Number of half-lives (n) =?

n = t / t₁/₂

n = 6/6

n = 1

Finally, we shall determine the amount of the sample remaining after 6 years (i.e 1 half-life) as follow:

Original amount (N₀) = 1.5 mg

Half-life (t₁/₂) = 6 years

Number of half-lives (n) = 1

Amount remaining (N) =.?

N = 1/2ⁿ × N₀

N = 1/2¹ × 1.5

N = 1/2 × 1.5

N = 0.5 × 1.5

N = 0.75 mg

Thus, 0.75 mg of the sample is remaining.

5 0
3 years ago
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