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2 years ago

Please an answer!!! will give brainliest

Mathematics

1 answer:

pishuonlain [190]2 years ago

6 0

The answer is D) {-1,-6}

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For the first two days of January, it snowed 2.4 inches each day For

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It snowed for 4 days

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3 years ago

How do you change 15/4 into a decimal

Tomtit [17]

Answer:3.75

Step-by-step explanation:

just divide

6 0

3 years ago

Read 2 more answers

The linear combination method is applied to a system of equations as shown. 4(.25x + .5y = 3.75) → x + 2y = 15 (4x – 8y = 12) →

Ket [755]

Answer:

x+2y=12-------(1)

x-2y=3---------(2)

Adding equations 1 and 2

we get

2x=18

x=9

Equation 1

9+2y=15

2y=15-9

2y=6

y=3

The solution of the given system is x=9, y=3

Step-by-step explanation

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3 years ago

Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat

nirvana33 [79]

Answer:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

$\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}$

And solving for $\frac{dh}{dt}$ we got:

$\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}$

We need to convert the rate given into m^3/min and we got:

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

5 0

3 years ago

Round 0.83,to the nearest thousandths<br> NEED HELP IMMEDIATELY!!!

Dafna1 [17]

0.008 i think this is the answer

5 0

3 years ago