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2 years ago

So you may see more than one post abt these bc its due at 11:59 lol

Mathematics

1 answer:

dusya [7]2 years ago

8 0

Answer:

quadrilateral

Step-by-step explanation:

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A volleyball player sets the ball in the air, and the height of the ball after t seconds is given in feet by h= -16^2+12t+6. A t

JulsSmile [24]

h=-16²+12t+6

8=-256+12t+6

256-6+8=12t

-258=12t

t=-258/12

t=21.5

7 0

3 years ago

It takes Jesse (2/3) hour to mow her backyard how much of the yard will be mowed will be mowed after (1/4) hour ?

bija089 [108]

Answer:

the answer is A

Step-by-step explanation:

here is a link to the question i got the answer from

ok i looked it up and you can learn more here: brainly.com/question/12687875

6 0

2 years ago

Someone please help me with this one

Anna35 [415]

Answer:

k=-2x+9

Step-by-step explanation:

-4x+6=k*2x-3

+3 +3

-4x+9=k*2x

/2x /2x

-2x+9=k

8 0

3 years ago

What is the perimeter of this quadrilateral?<br> (5,5)<br> (2, 4)<br> (4, 1)<br> (6, 1)

lbvjy [14]

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{5}~,~\stackrel{y_1}{5})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{4}) ~\hfill AB=\sqrt{[ 2- 5]^2 + [ 4- 5]^2} \\\\\\ AB=\sqrt{(-3)^2+(-1)^2}\implies \boxed{AB=\sqrt{10}} \\\\[-0.35em] ~\dotfill\\\\ B(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{1}) ~\hfill BC=\sqrt{[ 4- 2]^2 + [ 1- 4]^2}$

$BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) ~\hfill CD=\sqrt{[ 6- 4]^2 + [ 1- 1]^2} \\\\\\ CD=\sqrt{2^2+0^2}\implies \boxed{CD=2} \\\\[-0.35em] ~\dotfill\\\\ D(\stackrel{x_1}{6}~,~\stackrel{y_1}{1})\qquad A(\stackrel{x_2}{5}~,~\stackrel{y_2}{5}) ~\hfill DA=\sqrt{[ 5- 6]^2 + [ 5- 1]^2}$

$DA=\sqrt{(-1)^2+4^2}\implies \boxed{DA=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Perimeter}}{\sqrt{10}~~ + ~~\sqrt{13}~~ + ~~2~~ + ~~\sqrt{17}}~~ \approx ~~ 12.89$

8 0

2 years ago

The factorization below is missing two positive integers a and b. 6x^(3)+18x^(2)-240x=6x(x-a)(x+b) Factor the polynomial and the

Dvinal [7]

Answer:

a = 5

Step-by-step explanation:

Hello, please consider the following.

$6x^3+18x^2-240x=6x(x^2+3x-40)\\\\\text{** The sum of the zeroes is -3=-8+5 and the product is -40=-8*5. **}\\\\\text{** So, we can factorise. **}\\\\6x^3+18x^2-240x=6x(x^2+3x-40)=6x(x^2+8x-5x-40)\\\\=6x(x(x+8)-5(x+8))\\\\\large \boxed{=6x(x+8)(x-5)}$

So, a = 5.

Thank you.

7 0

3 years ago

So you may see more than one post abt these bc its due at 11:59 lol​

So you may see more than one post abt these bc its due at 11:59 lol