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lesya [120]
4 years ago
10

The Career Placement department at a university wants to administer a survey to determine student awareness of the resources off

ered. The department expects that student awareness of the Career Placement resources will vary significantly depending on how many years a student has attended the university, so they plan to randomly select 30 freshmen, 30 sophomore, 30 juniors, and 30 seniors. This type of sample can be best described as a:_______.(A) simple random sample.(B) systematic sample.(C) stratified sample.(D) cluster sample.(E) block sample.
Mathematics
1 answer:
Finger [1]4 years ago
6 0

Answer:

stratified sample

Step-by-step explanation:

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The average salary of all residents of a city is thought to be about $39,000. A research team surveys a random sample of 200 res
Rina8888 [55]

Answer:

z=\frac{40000-39000}{\frac{12000}{\sqrt{200}}}=1.179    

p_v =2*P(z>1.179)=2*[1-P(Z    

Step-by-step explanation:

Data given and notation    

\bar X=4000 represent the average score for the sample    

s=12000 represent the sample standard deviation    

n=200 sample size    

\mu_o =39000 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

z would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

State the null and alternative hypotheses.    

We need to apply a two tailed test.    

What are H0 and Ha for this study?    

Null hypothesis:  \mu = 39000    

Alternative hypothesis :\mu \neq 39000    

Compute the test statistic  

The sample size is large enough to assume the distribution for the statisitc normal. The statistic for this case is given by:    

z=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

We can replace in formula (1) the info given like this:    

z=\frac{40000-39000}{\frac{12000}{\sqrt{200}}}=1.179    

Give the appropriate conclusion for the test  

Since is a two tailed test the p value would be:    

p_v =2*P(z>1.179)=2*[1-P(Z    

Conclusion    

If we compare the p value and a significance level given for example \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, then the true population mean for the salary not differs significantly from the value of 39000.    

6 0
3 years ago
Can someone please help me
Nastasia [14]

Answer: I'm not to sure about this question its kind of confusing.

Step-by-step explanation:

5 0
3 years ago
Which expression is the radical form of x^3/4
seraphim [82]
4th root of x cubed
7 0
3 years ago
Which of the following could not be a value of n? side lengths of 9 and 13
daser333 [38]
The correct answer here would be D. And that is because, in a triangle, the sum of 2 of the sides has to be greater than the third side for all sides.  If we add 22 and 13 we get 35, and 35 is greater than 9, for sure. But if we add 13 and 9 we get 22 which is not greater than the third side length of 22; it would be collinear with the side length and it has to be greater than the side length.
8 0
4 years ago
Sophie is ordering a taxi from an online taxi service The taxi charges $3.50 just for the pickup and then an additional $1.25 pe
coldgirl [10]

Answer:

$8.50

And I’m sorry it looks like a number is missing from the second question

Step-by-step explanation:

3.5+(4*1.25)=8.5

5 0
2 years ago
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