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bazaltina [42]
3 years ago
8

1/4 + 2/3. Can anybody help me solve this?

Mathematics
2 answers:
weqwewe [10]3 years ago
8 0

Answer:

11/12

Step-by-step explanation:

Multiply 1/4 times 3/3 and 2/3 times 4/4. That gives you 3/12 + 8/12. Add that together and you get 11/12

Sidana [21]3 years ago
7 0

¼ + ⅔ = 11/12

Step-by-step explanation:

\begin{aligned}\frac{1}{4}+\frac{2}{3}&=\frac{3+8}{12}\\&=\bf\frac{11}{12}\end{aligned}

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Anvisha [2.4K]
The answer is 7. hope this helps
7 0
3 years ago
Find the gradient of the curve y = x^5/2 at the point where x = 4 <br><br><br>​
serious [3.7K]

Given:

The equation of the curve is:

y=x^{\frac{5}{2}}

To find:

The gradient of the given curve at the point where x = 4.

Solution:

We have,

y=x^{\frac{5}{2}}

Differentiate with respect to x.

y'=\dfrac{5}{2}x^{\frac{5}{2}-1}       [\because \dfrac{d}{dx}x^n=nx^{n-1}]

y'=\dfrac{5}{2}x^{\frac{3}{2}}

Substituting x=4, we get

y'=\dfrac{5}{2}(4)^{\frac{3}{2}}

y'=\dfrac{5}{2}(2^2)^{\frac{3}{2}}

Using properties of exponents, we get

y'=\dfrac{5}{2}(2)^{2\times \frac{3}{2}}         [\because (a^m)^n=a^{mn}]

y'=\dfrac{5}{2}(2)^{3}

y'=\dfrac{5}{2}(8)

y'=20

Therefore, the gradient of the given curve at the point where x = 4 is 20.

5 0
3 years ago
Find the 29th term of the arithmetic sequence 182,176,170
In-s [12.5K]

9514 1404 393

Answer:

  14

Step-by-step explanation:

The first term of the sequence is 182, and the common difference is 176-182=-6. So, the general term is ...

  an = a1 +d(n -1)

  an = 182 -6(n -1)

The 29th term will be ...

  a29 = 182 -6(29 -1)

  a29 = 14

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32000 is the equatorial diameter of Uranus
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