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vladimir2022 [97]
3 years ago
14

If f(x) = x2 + 7x and g(x) = 3x - 1, what is f(g(x))?

Mathematics
1 answer:
Burka [1]3 years ago
6 0

Answer:

f(g(x)) = 9x^2 + 15x - 6

Step-by-step explanation:

We are using function g(x) = 3x - 1 as the input to function f(x) = x^2 + 7x.

Starting with f(x) = x^2 + 7x, substitute g(x) for x on the left side and likewise substitute x^2 + 7x for each x on the right side.  We obtain:

f(g(x)) = (3x - 1)^2 + 7(3x - 1).

If we multiply this out, we get:

f(g(x)) = 9x^2 - 6x + 1 + 21x - 7, or

f(g(x)) = 9x^2 + 15x - 6

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Please help!! This is so confusing! 100 points!!
masya89 [10]

Answer:

The value of the expression given is:

  • 4

Step-by-step explanation:

First, you must divide the expression in three, and to the final, you can multiply it:

  1. [(3^8)*(2^(-5))*(9^0)]^(-2)
  2. [(2^(-2))/(3^3)]^4
  3. 3^28

Now, we can solve each part one by one:

<em>First part. </em>

  • 3^8 = 6561
  • 2^(-5) = 0.03125
  • 9^0 = 1 (Whatever number elevated to 0, its value is 1)
  • (6561 * 0,03125 * 1) = 205.03125

And we elevate this to -2:

  • 205.03125^-2 = 2<u>.378810688*10^(-5)</u> or <u>0.00002378810688 </u>

<em>Second part. </em>

  • 2^(-2) = 0.25
  • 3^3 = 27
  • 0.25 / 27 = 9.259259259 * 10^(-3) or 0.00925925925925

And we elevate this to 4:

  • 0.00925925925925^4 = <u>7.350298528 * 10^(-9)</u> or <u>0.000000007350298528 </u>

<em>Third Part. </em>

  • 3^28 = <u>2.287679245 * 10^13</u> or <u>22876792450000</u>

At last, we multiply all the results obtained:

  • 0.00002378810688 * 0.000000007350298528 * 22876792450000 = <u>3.999999999999999999</u> approximately <u>4</u>

<u><em>We approximate the value because the difference to 4 is minimal, which could be obtained if we use all the decimals in each result</em></u>.

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