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3 years ago

James ran 8 miles in 57.68. minutes. What was his average time per mile?

Mathematics

1 answer:

trapecia [35]3 years ago

8 0

Steps:
57.68÷8
=7.21minutes per hour
(p.s. make sure they don't want you to round!)

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hram777 [196]

Answer:

4/3

Step-by-step explanation:

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3 years ago

Can I get help with this? Thanks! :)

ycow [4]

Answer:

The answer is 17

Step-by-step explanation:

8^2+15^2=c^2

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3 years ago

PLEASE HELP ME WITH THIS!!!!!!!!

vlabodo [156]

Answer:

(9.5, 0) is in quadrant I. (-4, 7) is in quadrant II. (-1, -8) is in quadrant III.

Step-by-step explanation:

The negative signs say everything (quite literally). If there are no negative signs, it is in quadrant I. If there is one in the x-axis (the first number in an ordered pair), it is in quadrant II. If there are 2 negative signs, it is in quadrant III, and if there is one in the y-axis (the second number in an ordered pair), it is in quadrant IV.

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3 years ago

Find the following integral

ololo11 [35]

There's nothing preventing us from computing one integral at a time:

$\displaystyle \int_0^{2-x} xyz \,\mathrm dz = \frac12xyz^2\bigg|_{z=0}^{z=2-x} \\\\ = \frac12xy(2-x)^2$

$\displaystyle \int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy = \frac12\int_0^{1-x}xy(2-x)^2\,\mathrm dy \\\\ = \frac14xy^2(2-x)^2\bigg|_{y=0}^{y=1-x} \\\\= \frac14x(1-x)^2(2-x)^2$

$\displaystyle\int_0^1\int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy\,\mathrm dx = \frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx$

Expand the integrand completely:

$x(1-x)^2(2-x)^2 = x^5-6x^4+13x^3-12x^2+4x$

Then

$\displaystyle\frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx = \left(\frac16x^6-\frac65x^5+\frac{13}4x^4-4x^3+2x^2\right)\bigg|_{x=0}^{x=1} \\\\ = \boxed{\frac{13}{240}}$

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2 years ago

Review:

alex41 [277]

Answer:

Step-by-step explanation:

Well 6 to the second power is when you multiply 6 x 6 = 36

And ab= -320

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3 years ago