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3 years ago

Identify the initial condition in the table.

Mathematics

2 answers:

lubasha [3.4K]3 years ago

7 0

The given table can be represented as :

y = -x

And here, initial condition is 0

Digiron [165]3 years ago

4 0

Answer:

i had the answer but lost it ill look into more for u

Step-by-step explanation:

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I need help with how to solve this problem. It is #14. It already shows the answer (1point) but I need help on how to get there

Hitman42 [59]

Answer:

Option 4: 0.554

Step-by-step explanation:

As we can see that the intervals and their frequencies are given.

We have to calculate the probability of students' score falling between 70 and 89. It will use the frequency of both intervals 70-79 and 80-89.

So, combined scores of both intervals are:

172+105 = 277

Now to find the probability

= 277/500

=0.554

So option no 4 is the correct answer ..

7 0

3 years ago

What shape is this cross-section?

KIM [24]

Answer:

circle D

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!! THIS IS NOT A TEST OR AN ASSESSMENT!! Please help me with these math questions

Art [367]

Answer:

See below

Step-by-step explanation:

3. What are two ways that a vector can be represented?

Considering a vector $\vec{v}$ in some vector space $\mathbb R^n$ we have

$\vec{v} = \langle a,b\rangle$

This is the component form. I don't like that way. It is probably used in high school, but

$\vec{v} = \begin{pmatrix} a\\ b\\ \end{pmatrix}$

is preferable because the inner product on $\mathbb R^n$ is defined to be

$\langle a,b\rangle := \sum_{i = 1}^n a_i b_i$

You can also write it using linear form such as $\vec{v} = 2i+2j$

For this question, I think you meant

vectors

$\vec{u_1} = (-8, 12)$

$\vec{u_2} = (13, 15)$

Once

$\cos(\theta)=\dfrac{\vec{u_1} \cdot\vec{u_2}}{||\vec{u_1}||||\vec{u_2}||}$

Considering that the dot product is

$\vec{u_1}\cdot \vec{u_2} = (-8)\cdot 13 + 12\cdot 15 = -104+180= 76$

and the norm of $\vec{u_1}$ is $||\vec{u_1}|| = \sqrt{(-8)^2 + 12^2} = \sqrt{64 + 144}= \sqrt{208}$

and the norm of $\vec{u_2}$ is $||\vec{u_2}|| = \sqrt{13^2 + 15^2} = \sqrt{169 + 225}= \sqrt{394}$

Thus,

$\cos(\theta)=\dfrac{76}{\sqrt{208} \sqrt{394}} = \dfrac{19}{\sqrt{13}\sqrt{394}}=\dfrac{19}{\sqrt{5122}}$

$\therefore \theta = \arccos \left(\dfrac{19}{\sqrt{5122}} \right)$

3 0

2 years ago

What is 1/8 divided by 3/4?

nataly862011 [7]

Answer:

1 / 6 is the answer in fraction form and 0 . 16 as decimal form.

Step-by-step explanation:

1 / 8 ÷ 3 / 4

= 1 / 8 × 4 / 3

= 1 / 2 × 1 / 3

= 1 / 6

hope this answer will help you

6 0

3 years ago

There are 20 pieces of fruit in a bowl and 3 of them are oranges. What percentage of the pieces of fruit in the bowl are oranges

galben [10]

15 percent of the fruit in the fruit bowl are oranges

3 0

3 years ago