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joja [24]
2 years ago
14

What is the slope of the line that passes through the given points: (-2,8) and (4,6)?

Mathematics
2 answers:
garri49 [273]2 years ago
3 0

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Let's find the slope :

taking :

  • y_2 = 6

  • y_1 = 8

  • x_2 = 4

  • x_1 =  - 2

now, we know the formula to find the slope, that is :

  • \dfrac{y_2 - y_1}{x_2 -x_1 }

  • \dfrac{6 - 8}{4 - ( - 2)}

  • \dfrac{ - 2}{ 6}

  • - \dfrac{ 1}{3}

Semenov [28]2 years ago
3 0

Answer:

\boxed {-\frac{1}{3}}

Step-by-step explanation:

\boxed {\sf{Slope}=\cfrac{y_2-y_1}{x_2-x_1}}

\sf \left(x_1,\:y_1\right)=\left(-2,\:8\right)

\sf \left(x_2,\:y_2\right)=\left(4,\:6\right)

__________________

\sf slope \:(m)=\cfrac{6-8}{4-\left(-2\right)}

\boxed {\sf Subtract \:the \:numbers:-}

\sf Slope\:(m)=-\cfrac{1}{3}

__________________

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Answer:

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Step-by-step explanation:

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3 years ago
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2 years ago
What is the solutions of the equation 2 (x+2) ^2-4=28
JulsSmile [24]

Answer:

x = 2            x = -6

Step-by-step explanation:

2 (x+2) ^2-4=28

Add 4 to each side

2 (x+2) ^2-4+4=28+4

2 (x+2) ^2= 32

Divide by 2

2/2 (x+2) ^2=32/2

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Take the square root of each side

sqrt((x+2)^2) =±sqrt( 16)

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Subtract 2 from each side

x+2-2 = -2±4

x = -2±4

x = -2+4      and x = -2-4

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