Answer:
Correct option is
B
90
∘
,90
∘
,90
∘
Let AB and CD be two lines Intersecting at O, such that, ∠AOD=90
∘
Now, ∠AOD=∠COB=90
∘
(Vertically opposite angles)
⟹∠AOD+∠DOB=180
o
(Angles on a straight line)
⟹90+∠DOB=180
o
∠DOB=90
∘
∠DOB=∠AOC=90
∘
(Vertically opposite angles)
Thus, all angles are 90
∘
.
Answer:
Complement: 67°
Supplement: 157°
Step-by-step explanation:
Complementary angles = 90°
90-23=67°
Supplementary angles = 180°
180-23=157°
Answer:
Step-by-step explanation:
-5+-15= -20
4+15= 19
-20+19
-1
a^2 - b^2 = (a + b)(a - b)
In this case
49x^4y^2 - 4z^2
= (7x^2y)^2 - (2z)^2
= (7x^2y + 2z)(7x^2y - 2z)
Factors are (7x^2y + 2z) and (7x^2y - 2z)
Answer:
D) 7x^2y + 2z
This is one example of a trinomial with a leading coefficient of 3 and a constant term of -5