You would need to add 22 to 38 then divide that answer by 5 to get x
H = 3b+2
A = (h*b)/2 28 = (3b+2)b/2 56 = 3b²+2b 0 = 3b² + 2b - 56
⊕
![\left \{ {{y=2} \atop {x=2}} \right. \int\limits^a_b {x} \, dx \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \beta \\ \\ \\ x^{2} \sqrt{x} \sqrt[n]{x} \frac{x}{y} x_{123} x^{123} \leq \geq \pi \alpha \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] x_{123} \int\limits^a_b {x} \, dx \left \{ {{y=2} \atop {x=2}}](https://tex.z-dn.net/?f=%20%5Cleft%20%5C%7B%20%7B%7By%3D2%7D%20%5Catop%20%7Bx%3D2%7D%7D%20%5Cright.%20%20%5Cint%5Climits%5Ea_b%20%7Bx%7D%20%5C%2C%20dx%20%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20a_n%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D%20%20%5Cbeta%20%20%5C%5C%20%20%5C%5C%20%20%5C%5C%20%20x%5E%7B2%7D%20%20%5Csqrt%7Bx%7D%20%20%5Csqrt%5Bn%5D%7Bx%7D%20%20%5Cfrac%7Bx%7D%7By%7D%20%20x_%7B123%7D%20%20x%5E%7B123%7D%20%20%5Cleq%20%20%5Cgeq%20%20%5Cpi%20%20%5Calpha%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D%20%20x_%7B123%7D%20%20%5Cint%5Climits%5Ea_b%20%7Bx%7D%20%5C%2C%20dx%20%20%5Cleft%20%5C%7B%20%7B%7By%3D2%7D%20%5Catop%20%7Bx%3D2%7D%7D)
ω
l
∩
The set of real numbers for the equation x – 2 = √(2x – 1) will be 5.
<h3>What is the solution of the equation?</h3>
The solution of the equation means the value of the unknown or variable.
The equation is given below.
x – 2 = √(2x – 1)
Square on both side, then we have
(x – 2)² = 2x – 1
x² – 4x + 4 = 2x – 1
x² – 6x + 5 = 0
x² – 5x – x + 5 = 0
x(x – 5) – 1(x – 5) = 0
(x – 5)(x – 1) = 0
x = 1, 5
The set of real numbers for the equation x – 2 = √(2x – 1) will be 5.
More about the solution of the equation link is given below.
brainly.com/question/545403
#SPJ1
Polar form: (r,θ)
Using these formulas:
x²+y²=r²
tan(θ)=y/x
We have the point (1,1) in cartesian coordinates. We need to find r and θ to get it in polar form.
r²=1²+1²
r²=2
r=±√2
tan(θ)=1/1
tan(θ)=1
θ=π/4 radians or 45 degrees
Polar coordinates: (√2,π/4)
Those answer choices look strange. Are you sure these are the right answer choices?
