Answer:
First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.
For:
x
=
0
y
=
0
+
5
y
=
5
Or
(
0
,
5
)
For:
x
=
−
2
y
=
−
2
+
5
y
=
3
Or
(
−
2
,
3
)
We can now plot the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.
The boundary line will be solid because the inequality operator contains an "or equal to" clause.
graph{(x^2+(y-5)^2-0.125)((x+2)^2+(y-3)^2-0.125)(y-x-5)=0 [-20, 20, -10, 10]}
Now, we can shade the left side of the line.
graph{(y-x-5) >= 0 [-20, 20, -10, 10]}
Answer:
x= -3
x= -5
Step-by-step explanation:
x^2 + 8x + 15 = 0
find which 2 numbers when multiplied equal 15 and when added equal 8
they are 3 and 5
(x+3)(x+5)
x+3 =0
x+5=0
x= -3
x= -5
1.001 is greater than 0.111 because the 1 is automatically greater than zero. 1.11 is greater than 1.01 because there is a place in the tenths place in 1.11 but none for 1.01.
