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2 years ago

(4x + 3)(4x - 3) Help pls

Mathematics

2 answers:

tekilochka [14]2 years ago

6 0

Answer:

$16x^2-9$

Step-by-step explanation:

$\left(4x+3\right)\left(4x-3\right)$

We´ll Apply Difference Two Squares Formula:

$\left(a+b\right)\left(a-b\right)=a^2-b^2$

$\longmapsto$ $\left(4x+3\right)\left(4x-3\right)$

$\longmapsto$ $\left(4x\right)^2-3^2$

Apply exponent rule:

$\left(a\times \:b\right)^n=a^nb^n$

$\longmapsto$ $4^2x^2-3^2$

$\longmapsto$ $16x^2-9$

_________________________

Bingel [31]2 years ago

5 0

Answer:

Step-by-step explanation:

(4x + 3)(4x - 3)

Using identity, (a + b) (a - b) = a^2 - b^2

here, a = 4x + 3 and b = 4x - 3,

therefore,

=> (4x) ^2 - (3)^2

=> 16x^2 - 9... ans

<h2>HOPE IT HELPS U!!!!</h2>

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Long division 3x+1/6x^6+5x^5+2x^4-9x^3+7x^2-10x+2

inna [77]

$(6 x^{6}+5x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2) / (3x+1)$

We divide first number from first parenthesis with first number from second parenthesis. Then the resulting number we multiply by all numbers in second parenthesis and substract from first parenthesis.

$6 x^{6}/3x = 2 x^{5} \\ \\ 6 x^{6}+5x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2 - 6 x^{6} -2 x^{5} = 3x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2\\$

We repeat previous steps until we run out of numbers:
$3x^{5}/3x=x^{4} \\ \\ 3x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2-3x^{5}-x^{4}= \\ \\ x^{4}-9x^{3}+7x^{2}-10x+2 \\ \\ \\ x^{4}/3x= \frac{1}{3} x^{3} \\ \\ x^{4}-9x^{3}+7x^{2}-10x+2-x^{4}- \frac{1}{3} x^{3}= \\ \\ - \frac{28}{3} x^{3}+7x^{2}-10x+2 \\ \\ \\ - \frac{28}{3} x^{3}/3x= - \frac{28}{9} x^{2} \\ \\ - \frac{28}{3} x^{3}+7x^{2}-10x+2+ \frac{28}{3} x^{3}+ \frac{28}{9} x^{2} = \\ \\ \frac{91}{9} x^{2}-10x+2$
$\frac{91}{9} x^{2}/3x=\frac{91}{27} x \\ \\ \frac{91}{9} x^{2}-10x+2-\frac{91}{9} x^{2}-\frac{91}{27} x= \\ \\ -\frac{361}{27} x+2 \\ \\ \\ -\frac{361}{27} x/3x=-\frac{361}{81} \\ \\ -\frac{361}{27} x+2+\frac{361}{27}x+\frac{361}{27}= \\ \\ \frac{415}{27}$

We are left with a number that has no x inside. This is remainder.
The final solution is sum of all these solutions and remainder:
$(2 x^{5}+x^{4}+\frac{1}{3} x^{3} - \frac{28}{9} x^{2} +\frac{91}{27} x)+(-\frac{361}{81} )$

6 0

3 years ago

Zara translates figure p to make figure q. If she translates figure q 4 units to right to make figure r where will figure r be l

Morgarella [4.7K]

Using translation concepts, considering the vertices (x,y) of figure p, the following rule is applied to find the vertices of figure r.

(x,y) -> (x + 4, y).

<h3>What is a translation?</h3>

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s definition or in it’s domain. Examples are shift left/right or bottom/up, vertical or horizontal stretching or compression, and reflections over the x-axis or the y-axis.

When a figure is shifted 4 units to the right, 4 is added to the x-coordinate, hence, considering the vertices (x,y) of figure p, the following rule is applied to find the vertices of figure r.

(x,y) -> (x + 4, y).

More can be learned about translation concepts at brainly.com/question/28416763

#SPJ1

7 0

1 year ago

NEED HELP ASAP!

mote1985 [20]

Answer:

Step-by-step explanation:

You input will always be your x so you just substitute x with 10 and simplify. Which is 30 minus 6, thus 24. :)

7 0

2 years ago