Question

(4x + 3)(4x - 3) Help pls

Answer 1

Answer:

$16x^2-9$

Step-by-step explanation:

$\left(4x+3\right)\left(4x-3\right)$

We´ll Apply Difference Two Squares Formula:

• $\left(a+b\right)\left(a-b\right)=a^2-b^2$

$\longmapsto$ $\left(4x+3\right)\left(4x-3\right)$

$\longmapsto$ $\left(4x\right)^2-3^2$

Apply exponent rule:

• $\left(a\times \:b\right)^n=a^nb^n$

$\longmapsto$ $4^2x^2-3^2$

$\longmapsto$ $16x^2-9$

_________________________

Answer 2

Answer:

16x^2 - 9

Step-by-step explanation:

(4x + 3)(4x - 3)

Using identity, (a + b) (a - b) = a^2 - b^2

here, a = 4x + 3 and b = 4x - 3,

therefore,

=> (4x) ^2 - (3)^2

=> 16x^2 - 9... ans

HOPE IT HELPS U!!!!