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My name is Ann [436]
3 years ago
8

REPOSTING AGAIN, PLEASE GIVE SOLUTION AND PROOF IG. T-T and no clowning pls

Mathematics
1 answer:
fomenos3 years ago
3 0
A)
1) -3.4
2) -0.75
3) 0.375

B)
1) 2/25
2) 78/25
3) 501/100
You might be interested in
Find the distance between (-5 3) and (4 -5)​
ruslelena [56]

Answer:

19 or √145 ≈ 12.04

Step-by-step explanation:

Use the distance formula to determine the distance between the two points.

Distance  =  √ ( x ₂  −  x ₁ )²  +  ( y ₂  −  y ₁ ) ²

Substitute the actual values of the points into the distance formula.

√ ( 4  −  (  −  5 )) ²  +  ( ( − 5 ) − 3 ) ²

Simplify:  

√ 145

The result can be shown in multiple forms.

Exact Form:

√ 145

Decimal Form:

12.04159457  … ≈ 12.04

6 0
3 years ago
when 5 is subtracted from 3 times number the result greater than 6 .find the least whole number that satisfied the statement​
Alexandra [31]

Answer:

4

Step-by-step explanation:

Let x be a number.

The statement can be interpreted as:

  • 5 is subtracted <u>from</u> a number : x - 5
  • 3 times a number : 3x
  • A number is greater than 6 : x > 6
  • When 5 is subtracted <u>from</u> 3 times a number, the result is greater than 6 : 3x - 5 > 6

And then we simplify 3x - 5 > 6:

  • 3x - 5 > 6
  • 3x > 11
  • x > 11/3
  • x >  3.666...

To get the smallest whole number satisfying the inequality above, we can take the "ceiling" of 3.66 which is 4.

Note:

The ceiling of a number is the nearest integer (or in this case, nearest whole number) of a number. It can be denoted by ceil(x).

For example, the ceiling of 0.1 is 1. The ceiling of 5 is 5 since 5 itself is a integer.

3 0
4 years ago
Can someone please help
atroni [7]

Answer:

Step-by-step explanation:

1)

\frac{5}{24}+\frac{2}{3-x}=\frac{1}{4}\\\\\frac{5}{24}-\frac{1}{4}=\frac{-2}{3-x}\\\\\frac{5}{24}-\frac{1*6}{4*6}=\frac{-2}{3-x}\\\\\frac{5-6}{24}}=\frac{-2}{3-x}\\\\\frac{-1}{24}}=\frac{-2}{3-x}\\\\\\(-1)*(3-x)=(-2)*24\\\\-1*3-(-1)*x = -48\\\\-3 + x = -48\\\\x = -48 + 3\\\\x = -45

x = -45

2)

4 0
3 years ago
5. Prove that opposite angles of a cyclic quadrilateral are supplementary.
Temka [501]

Answer:

See attached for the cyclic quadrilateral

To prove: <BAD + <BCD =180°

Construction: Join B and D to the centre O of circle ABCD

Proof  

With the lettering of the attached drawing,

                         <BOD = 2y    (angle at centre is 2 X angle at circumference)

            Reflex <BOD   = 2x     (angle at centre is 2 X angle at circumference)

                    ∴ 2x + 2y = 360°    (angle at point)

                       ∴ x + y   = 180°                    

       ∴ <BAD + <BCD   = 180°            

Step-by-step explanation:

The vertices of a cyclic quadrilateral lie on the circumference of the circle and the opposite angles of a cyclic quadrilateral lie in opposite segment of a circle.

The question is to prove that the opposite angles of a cyclic quadrilateral are supplementary that is 180°. Another way of stating this theory is 'Angles in opposite segments are supplementary'.

Note that the sum of supplementary angles is 180°.

3 0
3 years ago
Solve: (2a^2+5a+2)^1/2=3<br><br> a = -7/2<br> a = 1<br> a = -7/2 or a = 1<br> no real solution
Nady [450]

Answer: c

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
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