All categories

2 years ago

Find the distance between (-5 3) and (4 -5)

Mathematics

1 answer:

ruslelena [56]2 years ago

6 0

Answer:

19 or √145 ≈ 12.04

Step-by-step explanation:

Use the distance formula to determine the distance between the two points.

Distance = √ ( x ₂ − x ₁ )² + ( y ₂ − y ₁ ) ²

Substitute the actual values of the points into the distance formula.

√ ( 4 − ( − 5 )) ² + ( ( − 5 ) − 3 ) ²

Simplify:

√ 145

The result can be shown in multiple forms.

Exact Form:

√ 145

Decimal Form:

12.04159457 … ≈ 12.04

You might be interested in

West of Checkpoint A, which is at (0,5), are two hurdles that Helena needs to jump over. Hurdle 1 is 4 units west of Checkpoint

elixir [45]

Answer:

Checkpoint B = (-9,5)

Step-by-step explanation:

Here is an image of the graph and coordinates.

4 0

3 years ago

the base of a ten foot ladder stands six feet from a house. How many feet up the house does the ladder reach

Ludmilka [50]

In this problem you will need to use the Pythagorean theorem (c^2=a^2+b^2).
The a and b represents the two edges, while c is the diagonal side and it is called the hypotenuse. Since you already know what the hypotenuse is and what one of the sides already are you just have to use the problem: c^2-a^2=b^2. Then if you plug the data you already have into the problem you will get 10^2-6^2=b^2. That then equals 100-36=b^2. Then you subtract and get b^2=64. Then you square root both sides and you get the answer b=8.

5 0

3 years ago

Convert: 76.8°f = ________ °c<br> a. 21.5<br> b. 25<br> c. 170.24<br> d. 24.89

lesya [120]

The answer to convert 76.8 fahrenheit to Celsius is D

3 0

3 years ago

Read 2 more answers

4(3x^2y^4)^3 / (2x^3y^5)^4

tatyana61 [14]

Solving the expressions $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$ we get $\frac{27}{4x^{6}y^{8}}$

Step-by-step explanation:

We need to Solve the expression: $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$

Solving:

$\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$

$=\frac{4(3^3x^6y^{12})}{(2^4x^{12}y^{20})}\\=\frac{4(27x^6y^{12})}{(16x^{12}y^{20})}\\=\frac{108x^6y^{12}}{16x^{12}y^{20}}$

Applying exponent rule: $\frac{x^a}{x^b}=x^{a-b}$

$=\frac{108x^{6-12}y^{12-20}}{16}\\=\frac{27x^{-6}y^{-8}}{4}$

Another exponent rule says: $x^{-a}=\frac{1}{x^a}=$

$=\frac{27}{4x^{6}y^{8}}$

So, solving the expressions $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$ we get $\frac{27}{4x^{6}y^{8}}$

Keywords: Solving Exponents

Learn more about Solving Exponents at:

#learnwithBrainly

8 0

3 years ago

Can you simplify 37/80

Setler [38]

Answer:

Step-by-step explanation:

37 is prime, so it's not possible to reduce/simplify 37/80. 37/80 is the ratio of two integers. We could, of course, use a calculator to find the decimal equivalent: 0.4625, but this is not more accurate than the ratio 37/80.

7 0

2 years ago

Find the distance between (-5 3) and (4 -5)​

Find the distance between (-5 3) and (4 -5)