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Galina-37 [17]
2 years ago
5

Please Help! I will give you a lot of points! (6.3)

Mathematics
1 answer:
Mandarinka [93]2 years ago
8 0

Let x be the yearly salary of an architect. Then the yearly salary of a lawyer is 2x-20000.

We can build an equation now! x+(2x-20000)=211000, because the yearly salary of an architect plus the yearly salary of a lawyer is 211000.

We combine like terms to get 3x-20000=211000.

We add 20000 to both sides to get 3x=231000.

We divide both sides by 3 to get x=77000, so the average yearly salary of a lawyer is 77000.

Then, the average yearly salary of an architect is 2(77000)-20000=154000-20000=134000, so the average yearly salary of an architect is 134000.

You might be interested in
The formula
Tasya [4]

Answer

the answer is P=7.8

Step-by-step explanation:

P=14.7e           -0.21x

X=14.7e      (-0.63)

take the natrual log of both sides

1n(P)=1n(14.7e(-.63)

1n(P)=1n(14.7)-.63

(because ln(e^a) = a)

1n(P)=2.688 - .63

1n(P)=2.058

P=e       2.058

P=7.8

3 0
3 years ago
RT has the endpoints (0, 2) and (4, 2). What is its midpoint?
Nimfa-mama [501]
R=(0,2), T=(4,2)
vector:
v=(4-0,2-2)=(4,0)
v/2=(2,0)

(0,2)+v/2=(2,2)

so (2,2) is the midpoint
3 0
3 years ago
Read 2 more answers
Using your knowledge of exponential and logarithmic functions and properties, what is the intensity of a fire alarm that has a s
Ierofanga [76]

Option B:

I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}

Solution:

Given sound level = 120 decibel

To find the intensity of a fire alarm:

$\beta=10\log\left(\frac{I}{I_0} \right)

where I_0=1\times10^{-12}\ \text {watts}/ \text m^2}

Step 1: First divide the decibel level by 10.

120 ÷ 10 = 12

Step 2: Use that value in the exponent of the ratio with base 10.

10^{12}

Step 3: Use that power of twelve to find the intensity in Watts per square meter.

$10^{12}=\left(\frac{I}{I_0} \right)

$10^{12}=\left(\frac{I}{1\times10^{-12}\ \text {watts}/ \text m^2} \right)

Now, do the cross multiplication,

I=10^{12}\times1\times\ 10^{-12} \ \text {watts}/ \text m^2}

I=1\times\ 10^{12-12} \ \text {watts}/ \text m^2}

I=1\times\ 10^{0} \ \text {watts}/ \text m^2}

I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}

Option B is the correct answer.

Hence I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}.

5 0
3 years ago
Really need help on my correction if anyone know please help!!
Olin [163]
Answers: 
<u>Question 19:</u> 177 bpm
<u>Question 20:</u> 95˚F

Explanations:
<u>Question 19:</u>
You had the formula set up properly like this:
R =  \frac{885 \sqrt{25} }{25}  =  \frac{885(5)}{25}  =  \frac{4425}{25} 
This is where you went wrong - I don't know exactly what you did, but your division of 4425 ÷ 25 is wrong. You should have ended up with 177 which is the correct answer. 
<u>Question 20:</u>
You had the formula set up correctly again, and merely used the wrong sign when adding 32. 
F =  \frac{9(35)}{5} + 32 =  \frac{315}{5} + 32
This is where you went wrong. You subtracted 32 from 63 when you should have added it. (See red circle on your subtraction.)
63 + 32 = 95˚F
7 0
3 years ago
Round 2.56×0.03 to the nearest hundredth
Arlecino [84]
2.56 times 0.03 is 0.0768 then round to hundredth is 0.08 i think 
4 0
3 years ago
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