4. If the determinant delta of a quadratic equation is positive, the equation has two real roots. If the determinant is negative, it has two imaginary roots. In this case, delta=b^2-4ac=(-1)^2-4*1*4=-15. Therefore, this equation has two imaginary roots.
None of the given choices is the correct solution.
The setup of the problem is a correct, if somewhat weird, description
of the ideal gas laws, but the temperature involved in the law is the
ABSOLUTE temperature, NOT the Celsius or Fahrenheit one, or
any other scale where 'zero' is not 'Absolute Zero'.
Zero Celsius is (about) 273 Celsius-size degrees above Absolute Zero.
So the original temperature of the gas is (273 + 2.5) = 275.5 Kelvins
(Celsius degrees above absolute zero). THAT's the temperature that's
going to change in inverse proportion to the volume.
(if the pressure doesn't change)
The volume has been multiplied by 100cm³/500cm³ = 1/5 .
Since the temperature changes inversely, it will be multiplied by 5 .
Final absolute temperature = (5) x (original absolute temperature) =
(5) x (275.5 K) =
1377.5 K .
The final Celsius temperature is (1377.5 - 273) = <em>1104.5 °C</em>.
"But those are the choices in the assignment !"
Then the person who wrote the question in the assignment is wrong.
None of the choices they gave is correct.
Answer:
x = 2
Step-by-step explanation:
180= 90 + 57 + Z
Z = 180 - 90 - 57
Z = 33
33 = 7X + 19
7X = 33 - 19
7X = 14
X = 2
3(1)+4<span>≥ 13
7</span><span>≥ 13
No
3(2.5)+4</span><span>≥ 13
11.5</span><span>≥ 13
No
3(3)+4</span><span>≥ 13
13</span><span>≥ 13
Yes
{3, 4.5, 5}</span>
Answer:
24 foot
Step-by-step explanation:
We are given that
Length of ladder=26 foot
Height of building=10 foot
We have to find the distance between the bottom of ladder and the bottom of building.
Pythagorus theorem:
We have hypotenuse =AC=26 foot
Perpendicular side =AB=10 foot
Base=BC
Substitute the values in the given formula
(Take positive because length is always positive)
BC=24 foot
Hence, the bottom of the ladder will be 24 foot from the bottom of the building.
