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Galina-37 [17]
2 years ago
11

A quantity with an initial value of 510 decays exponentially at a rate of 0.05% every 7

Mathematics
1 answer:
ludmilkaskok [199]2 years ago
7 0

Answer: its c trust me

Step-by-step explanation:

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What is the average (arithmetic mean) of eleven consecutive integers? (1) the average of the first nine integers is 7. (2) the a
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Since eleven is odd, there must be a centra element, which in this case is the sixth. So, we can write 11 consecutive integers as

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Since the arithmetic mean is the sum of the values, divided by how many they are, we have

M = \dfrac{x-5, x-4, x-3, x-2, x-1, x, x+1, x+2, x+3, x+4, x+5}{11} = \dfrac{11x}{11} = x

So, the mean of 11 consecutive integers is the 6th integer.

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3 years ago
If 3/5 of a chorus is singing. What fraction of the chorus is not singing?
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5/5 (one whole) - 3/5 = 2/5. 
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Which expressions are equivalent to 4x^4-9x^2?
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3 years ago
You bake a batch of muffins. You freeze 6 muffins and share the rest equally among yourself and 2 friends. Write an
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This makes sense to me: m=(y-6)/3

m is the number of muffins each friend gets, y is the original quantity of muffins, -6 is = to the number of muffins you freeze, and the /3 is to split the remaining (unfrozen) muffins equally.
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What is the range of possible sizes for side x? _ < x < _
qwelly [4]

Answer:

2.8 < x < 5.8

Step-by-step explanation:

We must apply the Triangle Inequality Theorem which states that for any triangle with sides a, b, and c:

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b + c > a

c + a > b

Here, let's arbitrarily denote a as 4.1, b as 1.3, and c as x. So, let's plug these values into the 3 inequalities listed above:

a + b > c  ⇒  4.1 + 1.3 > x  ⇒  5.8 > x

b + c > a  ⇒  1.3 + x > 4.1  ⇒  x > 2.8

c + a > b  ⇒  x + 4.1 > 1.3  ⇒  x > -2.8

Look at the last two: clearly if x is greater than 2.8 (from the second one), then it will definitely be greater than -2.8 (from the third), so we can just disregard the last inequality.

Thus, the range of possible sizes for x are:

2.8 < x < 5.8

<em>~ an aesthetics lover</em>

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